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If you know the angles in a triangle, it is theoretically possible to work out the ratio of the lengths of the sides. For strange angles, you need to use trigonometry to do that; for some angles we can do it by hand (for 30-60-90 triangles, 45-45-90 triangles, and for triangles like the one above that can be divided into familiar triangles).

So from the angles, we could find the ratio of w to x to y, and if we thus know w, or know x+y, we can find all three of the numbers w, x and y, and with those three lengths we can find the triangle's area. So the answer is D.

If you genuinely did want to solve this as a PS problem, you can draw a vertical height from B to AC. That splits the triangle into a 30-60-90 triangle on the left, and a 45-45-90 triangle on the right. You can then use the 45-45-90 and 30-60-90 triangle ratios to work out every length in terms of w.
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I am still not able to understand how B option can help in resolving the questions, can someone show me step by step approach using option B
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I am still not able to understand how B option can help in resolving the questions, can someone show me step by step approach using option B

To show that statement 2 is sufficient, we use the exact same approach we used to show that statement 1 is sufficient.
That is, each time we enlarge the original triangle by a little bit, each side length increases a little bit.
This also means that, each time we enlarge the triangle, the perimeter increases a little bit.
We can also say that, each time we enlarge the triangle a little bit, the sum of x and y increases a little bit.

This means, for each unique size of the triangle, there exists a unique sum of x and y.
In other words, there is exactly one unique triangle in which the sum of x and y is 3√2 + √6

For this reason, statement 2 is also sufficient.

Does that help?
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