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Let r - no. of red balls and b- no. of blue balls
r+b = 10 (given)
Statement 1: Prob(two reds) = 1/15
Hence, rC2 / 10C2 = 1/15
=> r(r-1) = 6
=> r=3
sufficent

Statment 2 : Prob (one of each r and b) = 7/15
Hence, (rC1*bC1)/ 10C2 = 7/15
=> r*b = 21
and r+b = 10 (given)
=> r,b =3,7
But, it doesn't tell us if r is 3 or 7
Hence, not sufficient

Correct answer - A
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This is how I thought about it.

R = ?

St1- P(two red) = 1/15

(r/10) x (r-1/ 9) = 1/15 <--- r is the number of reds
Sufficient.

St2 - P(blue and red) = 7/15

i) blue,red : b/10 x r/9
ii) red,blue: r/10 x b/9

(b/10 x r/9) + (r/10 x b/9) = rb / 45

Insufficient

Answer is A.
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Can anyone please explain option 2
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vibhor1902
Can anyone please explain option 2
Check better version of this question with proper solutions here: https://gmatclub.com/forum/a-box-contai ... 99940.html

TOPIC IS LOCKED.
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