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11 Nov 2020, 01:15
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
18% (01:36) correct
82%
(01:28)
wrong
based on 129
sessions
History
Date
Time
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Not Attempted Yet
If x and y are integers is y odd?
(1) \(y^{2x} +8\) is odd.
(2) \(y^7x\) is odd.
(1) \(y^{2x} +8\) is odd.
(2) \(y^7x\) is odd.
11 Nov 2020, 08:57
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Bunuel
In Statement 1, x can be zero. Then y^(2x) + 8 = y^0 + 8 = 1 + 8 = 9, so y can be anything at all, even or odd, and Statement 1 is not sufficient (but it would become sufficient, if we knew that x was positive).
In Statement 2, we're multiplying integers and getting an odd result. That only ever happens if you multiply odd integers, so x is odd, and y^7 is odd, which means y is odd. So the answer is B.
General Discussion
11 Nov 2020, 09:04
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Bunuel
1) only odd+even=odd; so y is odd Suff
2) only odd*odd=odd; so y is odd Suff
Answer D
