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Hi Bunuel,

Could you help in solving the problem.

If amount of work done by A in 6 Hrs = A and amount of work done by B in 6 Hrs = B then

Total work done in 6 hours in 1 day if A and B are working together = A+B

Since both completes the work in 4 days, working together all 4 days and 6 Hrs each, the amount of work involved = 4(A+B)

If the same amount of work is done on alternate days by A and B alone, number of days to complete 4(A+B) work should be 8 days.

Where I am getting wrong ?
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ProfChaos
A works for 6 hours a day and B also works for 6 hours a day. What will be the number of days required to complete the work if only one of A and B work on any given day?

Statement 1: A and B working together for 6 hours everyday can complete the work in 4 days.
Statement 2: A and B work 6 hours per day on alternate days to complete the work.

Source: Indian B-school entrance exam


S1. Not sufficient since the rates of doing work by A and B isn't given.

S2. Not sufficient since we don't know how many days the work lasted.

Combining: we have the following:

(A = work of A in 6 hrs and B = work of B in 6 hrs)

[AB] - [AB] - [AB] - [AB]
Day1 - Day2 - Day3 - Day4

If it is done by A and B alternatively, we get:

[A]-{B}-[A]-{B}-[A]-{B}-[A]-{B}
D1 -D2 -D3 -D4 -D5 -D6 -D7 -D8

Thus, it takes 8 days - Sufficient

Answer C

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