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07 Dec 2020, 08:45
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
51% (01:43) correct
49%
(01:55)
wrong
based on 86
sessions
History
Date
Time
Result
Not Attempted Yet
What is the value of \(\frac{8a+a-b}{a-b}\)?
(1) \(\frac{5a + 4b}{ a - b} = 2\)
(2) \(a - b = 9\)
(1) \(\frac{5a + 4b}{ a - b} = 2\)
(2) \(a - b = 9\)
07 Dec 2020, 08:51
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Asked: What is the value of \(\frac{8a+a-b}{a-b}\)?
\(\frac{8a+a-b}{a-b}= \frac{8a}{a-b} + 1 = 8 + \frac{8b}{a-b} + 1 = 9 + \frac{8b}{a-b}\)
(1) \(\frac{5a + 4b}{ a - b} = 2\)
\(\frac{5a + 4b}{ a - b} = 5 + \frac{9b}{a-b}= 2\)
\(\frac{9b}{a-b} = -3\)
\(\frac{b}{a-b} = -1/3\)
\(\frac{8a+a-b}{a-b}= \frac{8a}{a-b} + 1 = 8 + \frac{8b}{a-b} + 1 = 9 + \frac{8b}{a-b}= 9 + 8*(-1/3) = 9 - 8/3 = 19/3\)
SUFFICIENT
(2) \(a - b = 9\)
We need ratio of a/a-b or b/a-b
NOT SUFFICIENT
IMO A
\(\frac{8a+a-b}{a-b}= \frac{8a}{a-b} + 1 = 8 + \frac{8b}{a-b} + 1 = 9 + \frac{8b}{a-b}\)
(1) \(\frac{5a + 4b}{ a - b} = 2\)
\(\frac{5a + 4b}{ a - b} = 5 + \frac{9b}{a-b}= 2\)
\(\frac{9b}{a-b} = -3\)
\(\frac{b}{a-b} = -1/3\)
\(\frac{8a+a-b}{a-b}= \frac{8a}{a-b} + 1 = 8 + \frac{8b}{a-b} + 1 = 9 + \frac{8b}{a-b}= 9 + 8*(-1/3) = 9 - 8/3 = 19/3\)
SUFFICIENT
(2) \(a - b = 9\)
We need ratio of a/a-b or b/a-b
NOT SUFFICIENT
IMO A
ananya3
Current Student
Joined: 05 Oct 2018
Last visit: 17 Dec 2022
Posts: 106
Given Kudos: 152
Location: India
Schools: Fuqua '24 Haas '24 ISB '23 Johnson '24 Kelley '24 Kenan-Flagler '24 McDonough '24 NUS Ross '24 Tepper '24 Tuck '24 Rotman '24 (A)
GMAT 1: 700 Q49 V36
GPA: 3.87
Schools: Fuqua '24 Haas '24 ISB '23 Johnson '24 Kelley '24 Kenan-Flagler '24 McDonough '24 NUS Ross '24 Tepper '24 Tuck '24 Rotman '24 (A)
GMAT 1: 700 Q49 V36
Posts: 106
07 Dec 2020, 22:53
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IMO A
\(\frac{(8a+a-b)}{(a-b)}\) = ?
=> \(\frac{(9a-b)}{(a-b)}\) = ?
(1) \(\frac{(5a+4b)}{(a-b)} = 2\)
=> 5a + 4b = 2a - 2b
=> 3a + 6b = 0
=> 3 (a+2b) = 0
=> a = -2b
now there is only one term and therefore we can get the answer - sufficient
\(\frac{(9(-2b) - b) }{(-2b-b)} = \frac{19}{3}\)
(2) a−b=\(9/m\)
=> \(\frac{(8a + 9)}{9} = \frac{8a}{9} + 1\)
Insufficient
\(\frac{(8a+a-b)}{(a-b)}\) = ?
=> \(\frac{(9a-b)}{(a-b)}\) = ?
(1) \(\frac{(5a+4b)}{(a-b)} = 2\)
=> 5a + 4b = 2a - 2b
=> 3a + 6b = 0
=> 3 (a+2b) = 0
=> a = -2b
now there is only one term and therefore we can get the answer - sufficient
\(\frac{(9(-2b) - b) }{(-2b-b)} = \frac{19}{3}\)
(2) a−b=\(9/m\)
=> \(\frac{(8a + 9)}{9} = \frac{8a}{9} + 1\)
Insufficient
