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given, Sqrt (A∗B∗C)=504= (2^3)*(3^2)*7, so A*B*C = (2^6)*(3^4)*(7^2)

Stat1: C = 168 = (2^3)*3*7
So, A*B = (2^3)*(3^3)*(7^1), now, B can be divisible by 2 or not. Not sufficient.

Stat2: A is a perfect square
So, A*B*C = (2^6)*(3^4)*(7^2), now, B can be divisible by 2 or not. Not sufficient.

Combining Stat 1 and 2,
A*B = (2^3)*(3^3)*(7^1), and A is a perfect square, so for B, we have always one 2 left. Sufficient

So, I think C. :)
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504 = 2*2*2*3*3*7
so A*B*C = 2*2*2*2*2*2*3*3*3*3*7*7

Statement 1: C=168 = 2*2*2*3*7
=> A*B = 2*2*2*3*3*3*7
As we don't know the value of A so this statement is not sufficient.

Statement 2: A is a perfect square
As there are six 2s, four 3s and two 7s so, there are many perfect squares.
So, this statement is also not sufficient.

Combining Statements A and B:
C= 2*2*2*3*7
A*B = 2*2*2*3*3*3*7
If A is a perfect square then it can have maximum of two 2s which means one of the 2 will be left. So, B will always be a multiple of 2.

So, correct answer is C.
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Is the answer E?
Couldn't we just use knowledge of odd/even to figure this one out?
From the stem, we see that the\( \sqrt{ABC}\) gives us 504. This tells us that ABC MUST be an even perfect square.

Statement 1 - C = 168
1. a is even, b is even, c is even YES b is divisible by 2
2. a is odd, b is even, c is even YES
3. a is even, b is odd, c is even NO
Insufficient

Statement 2 - a is a perfect square
This means a could be odd or even, doesn't tell us anything about B

Combined:
Well if b could be even or odd, we don't know.
Insufficient

Answer: E
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Bunuel
If A, B, and C are positive integers and \(\sqrt{A*B*C}=504\), is B divisible by 2?

(1) C = 168
(2) A is a perfect square


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Q - is b even
(Abc) = 504 * 504 or abc = even
1) c = 168 even insufficient
2) a is a perfect sq
A can end in
1,4,5,9,6 insufficient
1&2 )
Ab = (504*504/168) or even
Even * even = even
Od * even = even
A can be both od/even
So b has to be even. And divisible by 2
Hence ans C

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