fozzzy
What's the OA for this question?
In the number 1.4ab5, a and b represent single positive digits. If x = 1.4ab5, what is the value of 10 – x?Given: \(x = 1.4ab5\).
Notice that we need to find the values of a and b.
(1) If x is rounded to the nearest hundredth, then 10 – x = 8.56 --> x rounded to the nearest hundredth is 1.44, which implies that \(a\) can be 3 if \(b\geq{5}\) or 4 if \(b<{5}\). Not sufficient.
(2) If x is rounded to the nearest thousandth, then 10 – x = 8.564 --> x rounded to the nearest thousandth is 1.436. So, \(a=3\) and \(b=5\) (since the ten-thousandths digit is 5, then thousandths digit is rounded up, thus b is 1 less than 6, so 5). Sufficient.
Answer: B.
Rounding rulesRounding is simplifying a number to a certain place value. To round the decimal drop the extra decimal places, and if the first dropped digit is 5 or greater, round up the last digit that you keep. If the first dropped digit is 4 or smaller, round down (keep the same) the last digit that you keep.Example:
5.3485 rounded to the nearest tenth = 5.3, since the dropped 4 is less than 5.
5.3485 rounded to the nearest hundredth = 5.35, since the dropped 8 is greater than 5.
5.3485 rounded to the nearest thousandth = 5.349, since the dropped 5 is equal to 5.
Place Values
Hope it helps.
Attachment:
Place Values.png [ 38.87 KiB | Viewed 31218 times ]