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Bunuel
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sumitkrocks
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I just solved it this way. hopefully it's correct:

(1) x = 3q+2 - multiple values possible for x. not sufficient

(2) x^2 = 3q+1 - multiple values still possible for x. not sufficient.

(1) + (2) = just equate the two equations above:
(3q+2)^2 = 3q+1
9q^2 + 12q + 4 = 3q+1
9q^2 + 9q + 3 = 0
3(3q^2 + 3q + 1) = 0
null set

or if I solved it rigorously, x=2 is possible for (1) and (2). The next possible value for (1) is x=5, which is still possible for (2). hence both statements still are insufficient to get a specific value x.

Hence I answered E
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can anyone explain this?
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We're asked to find a value, but all we're given are remainders, and you can't find values from remainders alone. We can confirm that x can have different values here: if x = 2, then both statements are true, and if x = 5, both statements are true (or if you prefer, you could test x = 5 and x = 8, or literally any two values that give a remainder of 2 when divided by 3). So the answer is E.
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Not correct
Perhaps you mean 2, 5, 8, 11, ...
Gmatmenow
Not correct
Perhaps you mean 7 and 11 not 9 and 15

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