An apartment complex offers only 1-room and 2-room units. If the range

Question

An apartment complex offers only 1-room and 2-room units. If the range of total rental fees for both 1-room and 2-room units combined is $1,000, and the range of the rental fees for 2-room units is $200, what is the range of the rental fees for 1-room units?

(1) The lowest rental fee for a 2-room unit is $2,800.

(2) The lowest rental fee for a 2-room unit is $200 more than the highest rental fee for a 1-room unit.

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A certain apartment has only 1-room and 2-rooms. If the range of the total rental fees for 1-room and 2-rooms combined is $1,000 and the range of the rental fees for 2-rooms is $200, what is the range of the rental fees for 1-room?

(1) The smallest rental fee for 2-rooms is $2,800.

(2) The smallest rental fee for 2-room is $200 more expensive than the greatest rental fee for 1-room.

AbhinavShah14 · Answer

Could anyone show the calculations for this answer??

hahuynh · Answer

M1: max 1-room
m1: min 1-room
M2: max 2-room
m2: min 2-room

We have:
"the range of total rental fees for both 1-room and 2-room units combined is $1,000"
-> M2 - m1 = 1000
"the range of the rental fees for 2-room units is $200"
-> M2 - m2 = 200

Question:
"the range of the rental fees for 1-room units"
-> M1 - m1 = ?

(1) The lowest rental fee for a 2-room unit is $2,800.
m2 = 2800
-> cannot answer

(2) The lowest rental fee for a 2-room unit is $200 more than the highest rental fee for a 1-room unit.
m2 - M1 = 200
M1 - m1 = (m2 - 200) - m1 = m2 - m1 - 200 = (M2-200) - (M2-1000) - 200 = OK

=> B

chetan2u · Answer

Range is the largest - lowest. The main question statement tells us When we arrange the rentals of ALL rooms, the range is $1000. The range of rentals for 2-room is $200, and we have to find the range of rental fees for 1-room. We do not require to know exact amounts but only where does the range of 2-room rentals fit in over all range. a) If the $200 range is somewhere in between, the highest and lowest of all will be highest and lowest of 1-room rentals. So, the range will be 1000 itself. b) If the 200 range is at either end, then we would require some more info. Let us see if any statement gives us a clue on the above. (1) The lowest rental fee for a 2-room unit is $2,800. Just gives Highest 2-room rental as $3000. Nothing about the range. Insufficient (2) The lowest rental fee for a 2-room unit is $200 more than the highest rental fee for a 1-room unit. This tells us that L2 is 200 more than H1 => L2=H1+200 Further inference Lowest of all is L1 and highest of all is H2. L1…………H1….200…..L2…..200……H2 H1-L1 = 1000-200-200 = 600 Sufficient B Attached is a video on the same https://m.youtube.com/watch?v=a8rgbv_uUm0&t=12s

An apartment complex offers only 1-room and 2-room units. If the range

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GMAT Data Sufficiency (DS) Questions

An apartment complex offers only 1-room and 2-room units. If the range

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