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gmatophobia

Gangadhar111990
­130 passengers flying on a plane have stored a total of 250 pieces of luggage in the plane's cargo hold. If every passenger has stored at least 1 piece of luggage, how many of the passengers have stored exactly 2 pieces of luggage in the plane's cargo hold?

(1) 40 of the passengers stored only 1 piece of luggage in the cargo hold.

(2) None of the passengers stored more than 3 pieces of luggage in the cargo hold.



 
­Number of extra luggage = \(250 - 130 = 120\)

Statement 1

(1) 40 of the passengers stored only 1 piece of luggage in the cargo hold.

Number of people who stored more than 1 piece of luggage in the cargo hold = 130 - 40 = 90

However, we can't infer of these 90 passengers how many passengers stored exactly 2 pieces of luggage in the plane's cargo hold.

Hence, this statement alone is not sufficient and we can eliminate A, and D.

Statement 2

(2) None of the passengers stored more than 3 pieces of luggage in the cargo hold.

Let the number of passengers who stored exactly 2 pieces of luggage = x

Let the number of passengers who stored exactly 3 pieces of luggage = y

From the question premise, we know that \(2x + 3y = 120\)

We have two variables and one equation; multiple possible combinations of x and y satisfy this equation. Hence, we cannot infer the values of x and y.

Hence, eliminate B

Combined

Let the number of passengers who stored exactly 2 pieces of luggage = x

Let the number of passengers who stored exactly 3 pieces of luggage = y

From the question premise, we know that \(2x + 3y = 120\)

From statement 1, we can infer that \(x + y = 90\)

Combining the two equations we can find the value of x, and y.

The statements combined are sufficient.

Option C
 ­
­Hi. While combining statements 1 and 2, I got y=-60, can we consider this? Kindly help to find my gap in understanding. Thank you in advance.
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samarpan.g28

gmatophobia

Gangadhar111990
­130 passengers flying on a plane have stored a total of 250 pieces of luggage in the plane's cargo hold. If every passenger has stored at least 1 piece of luggage, how many of the passengers have stored exactly 2 pieces of luggage in the plane's cargo hold?

(1) 40 of the passengers stored only 1 piece of luggage in the cargo hold.

(2) None of the passengers stored more than 3 pieces of luggage in the cargo hold.




 
­Number of extra luggage = \(250 - 130 = 120\)

Statement 1

(1) 40 of the passengers stored only 1 piece of luggage in the cargo hold.

Number of people who stored more than 1 piece of luggage in the cargo hold = 130 - 40 = 90

However, we can't infer of these 90 passengers how many passengers stored exactly 2 pieces of luggage in the plane's cargo hold.

Hence, this statement alone is not sufficient and we can eliminate A, and D.

Statement 2

(2) None of the passengers stored more than 3 pieces of luggage in the cargo hold.

Let the number of passengers who stored exactly 2 pieces of luggage = x

Let the number of passengers who stored exactly 3 pieces of luggage = y

From the question premise, we know that \(2x + 3y = 120\)

We have two variables and one equation; multiple possible combinations of x and y satisfy this equation. Hence, we cannot infer the values of x and y.

Hence, eliminate B

Combined

Let the number of passengers who stored exactly 2 pieces of luggage = x

Let the number of passengers who stored exactly 3 pieces of luggage = y

From the question premise, we know that \(2x + 3y = 120\)

From statement 1, we can infer that \(x + y = 90\)

Combining the two equations we can find the value of x, and y.

The statements combined are sufficient.

Option C
 ­
­Hi. While combining statements 1 and 2, I got y=-60, can we consider this? Kindly help to find my gap in understanding. Thank you in advance.
The equations in the solution you quoted are not correct. They should be 2x + 3y = 210 (40 of the passengers stored only 1 piece of luggage, thus 250 - 40 = 210 pieces of luggage were stored by the passengers who stored more than 1 piece) and x + y = 90, which give x = 60 and y = 30.
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