Gangadhar111990
130 passengers flying on a plane have stored a total of 250 pieces of luggage in the plane's cargo hold. If every passenger has stored at least 1 piece of luggage, how many of the passengers have stored exactly 2 pieces of luggage in the plane's cargo hold?
(1) 40 of the passengers stored only 1 piece of luggage in the cargo hold.
(2) None of the passengers stored more than 3 pieces of luggage in the cargo hold.
Number of extra luggage = \(250 - 130 = 120\)
Statement 1(1) 40 of the passengers stored only 1 piece of luggage in the cargo hold.Number of people who stored more than 1 piece of luggage in the cargo hold = 130 - 40 = 90
However, we can't infer of these 90 passengers how many passengers stored exactly 2 pieces of luggage in the plane's cargo hold.
Hence, this statement alone is not sufficient and we can eliminate A, and D.
Statement 2(2) None of the passengers stored more than 3 pieces of luggage in the cargo hold.Let the number of passengers who stored exactly 2 pieces of luggage = x
Let the number of passengers who stored exactly 3 pieces of luggage = y
From the question premise, we know that \(2x + 3y = 120\)
We have two variables and one equation; multiple possible combinations of x and y satisfy this equation. Hence, we cannot infer the values of x and y.
Hence, eliminate B
CombinedLet the number of passengers who stored exactly 2 pieces of luggage = x
Let the number of passengers who stored exactly 3 pieces of luggage = y
From the question premise, we know that \(2x + 3y = 120\)
From statement 1, we can infer that \(x + y = 90\)
Combining the two equations we can find the value of x, and y.
The statements combined are sufficient.
Option C
Hi. While combining statements 1 and 2, I got y=-60, can we consider this? Kindly help to find my gap in understanding. Thank you in advance.