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Hanna holds a certain number of cards, each of which is green or black or yellow. If a person picked up a card randomly from the cards that Hannah is holding, is the probability that the card is black equal to 2/5?
(1) Hannah holds a total of 16 cards.
(2) Hannah holds 3 green cards, 7 black cards and 6 yellow cards.
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(1) Hannah holds a total of 16 cards.
(2) Hannah holds 3 green cards, 7 black cards and 6 yellow cards.
_________________
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Bunuel
(1) Hannah holds a total of 16 cards.
The probability cannot be \(\frac{2}{5}\) because \(16\) is not a multiple of \(5.\)
SUFF.
(2) Hannah holds 3 green cards, 7 black cards and 6 yellow cards.
This says the same thing as statement 1. We can answer a definite NO.
SUFF.
Just a little more explanation in case required: The denominator stands for the total number of cases or its reduced form. If the reduced form is \(5\), then the total number of cases has to be a multiple of \(5\). In both statements, we see that the total number of cases is NOT a multiple of 5. Hence, both statements individually are SUFF.
Ans D
Hope it helped.
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