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even if it meant \(|C-A|<15\), and \(A\geq{C}\), then there are more Adults than Children. It will meet the required ratio.

and when \(A<{C}\), as explained, minimum number of Adults will be when \(C-A=14\)


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\(Adults+Children=a+c=24\)

Required ratio of Children to Adults \(= \frac{c}{a}=\frac{4}{1}=4\)

To meet insurance terms, the ratio should be \(\frac{c}{a}<4\)

is \(\frac{c}{a}<4?\)

Statement 1: The difference between the number of children and the number of adults is smaller than 15

\(c-a<15\).

For minimum number of adults, \(c-a=14\)

We have two equations, \(c-a=14\) & \(c+a=24\)

\(c=19, a=5\)

\(\frac{c}{a}=\frac{19}{5}=3.8\)

Sufficient

Statement 2: If one more adult arrives at the nursery and one child is picked up by their parents, the ratio of adults to children will be 1:3

\(\frac{a+1}{c-1}=\frac{1}{3}\)

\(3a+3=c-1\)

\(c-3a=4\)

\(c+a=24\)

Sufficient

Answer: D
if difference is given then wouldn't be it like |C-A| <15
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