Bunuel
Rob’s latest meal contained 660 calories, derived from either protein or fat. Rob consumed x grams of protein, at y calories per gram and (120 – x) grams of fat, at (y + 5) calories per gram. Did Rob consume more protein or more fat?
(1) If Rob had consumed 10 more grams of protein and 20 more grams of fat, his meal would have contained 880 calories.
(2) If Rob had consumed (120 – x) grams of protein and x grams of fat, his meal would have contained greater than 660 calories.
Interesting DS question.
Given :
Consumption of protein = x gm
Consumption of fat = 120-x gm
calories per gm
protein = y per gm
fat = (y+5) per gm
total calories = 660
we need to find : Is x > 120-x ?
660 = xy + (120-x) (y+5)
solving we get,
60 = 120 y - 5x
12 = 24 y -x ———————————> equation 1
STATEMENT 1: (1) If Rob had consumed 10 more grams of protein and 20 more grams of fat, his meal would have contained 880 calories.
880 = (x+10)* y + (140 -x ) * (y+5)
180 = 150 y -5x
36 = 30 y - x —————— > equation 2
Subracting eqn 1 and eqn 2, we get
6y =24
y= 4 and x = 84 x = 84, 120-x < 84. Hence,
STATEMENT 1 is SUFFICIENT STATEMENT 2: (2) If Rob had consumed (120 – x) grams of protein and x grams of fat, his meal would have contained greater than 660 calories.
(120-x)*y + x *(y+5) > 660
120y + 5x > 660
24y + x > 132 ——————-> equation 3 adding eqn 1 and ean 3, we get 48 y > 144
y > 3
if y > 3, substitute in equation 3, we get
x > 60 if X > 60, then 120-x < 60 Hence STATEMENT 2 is SUFFICIENT. Both, the statements are individually sufficient to answer.
OPTION D