ExpertsGlobal5
Together, Pump A and Pump B can drain a particular tank in 2 hours and 24 minutes. How many hours would it take Pump A to drain the tank alone?
(1) Pump A alone can drain the tank in 2/3 the time that Pump B alone can.
(2) Pump A alone can drain the tank 2 hours faster than Pump B alone can.
Explanation: Let the time taken by pump A to drain the tank be M mins.
Let the time taken by pump B to drain the tank be N mins.
Since (Drain Rate) x (Time taken) = (Total tank volume):
Drain rate of pump A = (1/M) of total tank volume per min.
Drain rate of pump B = (1/N) of total tank volume per min.
Drain rate of pump A and B together = (1/M) + (1/N)
(Drain rate of pump A and B together) x (Time taken together) = Total tank volume
[(1/M) + (1/N)] x (2 hours and 24 minutes) = Total tank volume
[(1/M) + (1/N)] x (144 minutes) = Total tank volume
[(1/M) + (1/N)] = (1/144) of total tank volume per min (Equation I)
We need to find whether the value of “M/60” can be determined. Statement (1) M = (2/3)N (Equation II)
From Equation I and II, we have two equations with two unknown variables, which can be solved to determine the exact value of M.
It is possible to determine with certainty the number of hours taken by Pump A to drain the tank alone.
Hence, Statement (1) is sufficient. Statement (2) M = N – 120 (Equation III)
From Equation I and III, we have two equations with two unknown variables, which can be solved to determine the exact value of M.
It is possible to determine with certainty the number of hours taken by Pump A to drain the tank alone.
Hence, Statement (2) is sufficient. D is the correct answer choice.