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11 Dec 2025, 23:37
Kudos
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
68% (01:35) correct
32%
(01:39)
wrong
based on 165
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Together, Pump A and Pump B can drain a particular tank in 2 hours and 24 minutes. How many hours would it take Pump A to drain the tank alone?
(1) Pump A alone can drain the tank in 2/3 the time that Pump B alone can.
(2) Pump A alone can drain the tank 2 hours faster than Pump B alone can.
(1) Pump A alone can drain the tank in 2/3 the time that Pump B alone can.
(2) Pump A alone can drain the tank 2 hours faster than Pump B alone can.
12 Dec 2025, 01:44
Kudos
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Hello ,
Together, Pump A and Pump B can drain a particular tank in 2 hours and 24 minutes. How many hours would it take Pump A to drain the tank alone?
(1) Pump A alone can drain the tank in 2/3 the time that Pump B alone can.
If the time of A is 2/3 of time B then the Rate of A will be 3/2 of Rate of B
so we can calculate the answer
Hence Sufficient
(2) Pump A alone can drain the tank 2 hours faster than Pump B alone can.
As we know the time relative each other then we can calculate the required answer
Hence Sufficient
Correct Answer is D
Together, Pump A and Pump B can drain a particular tank in 2 hours and 24 minutes. How many hours would it take Pump A to drain the tank alone?
(1) Pump A alone can drain the tank in 2/3 the time that Pump B alone can.
If the time of A is 2/3 of time B then the Rate of A will be 3/2 of Rate of B
so we can calculate the answer
Hence Sufficient
(2) Pump A alone can drain the tank 2 hours faster than Pump B alone can.
As we know the time relative each other then we can calculate the required answer
Hence Sufficient
Correct Answer is D
12 Dec 2025, 10:04
Kudos
Bookmarks
ExpertsGlobal5
Time taken by pump A and pump B together = Ta + Tb = 2 hrs 24 minutes = 120+24 = 144 minutes.
We need to find time taken by pump A.
Statement 1:
(1) Pump A alone can drain the tank in 2/3 the time that Pump B alone can.
Ta = (2/3)* Tb
Ta : Tb = 2:3.
Time is inversely proportional to the rate.
Ra : Rb = 3:2
Total Rates = 3K + 2K = 5K
Work = Rate * Time = 5K * 144 = 720K
Time taken by A = Ta = 720K / 3K = 240 minutes = 4*60 minutes = 4 hours.
Hence, Sufficient.
Statement 2:
(2) Pump A alone can drain the tank 2 hours faster than Pump B alone can.
Tb = Ta+(2*60) = Ta+120
Total rate ( Ra + Rb) = Work / (Ta+Tb)
= Work / 144
(1/Ta) + (1/Ta+120) = 1/144
Solving Ta = 240 = 4 hrs.
Hence, Sufficient
Option D
