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Bunuel
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Bunuel
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To know, whether: n>m ?

Statement (1),

B takes half the time of A for a Junior order.

Time per Junior:

B = \([/5], A = n \\
\\
Given:\\
\\
[m][/5]=[n][/2]\\
2m=5n\\
m=2.5n\\
\\
So:\\
m>n ⇒ n<m\\
\\
We can answer the question, so it's→ Sufficient\\
\\
\\
Statement (2)\\
[5]\) > [3][/2] . [1][/n]

10n>3m

This does not guarantee whether n>m or n<m.
Both possible → So, It's not sufficient.

Therefore Option A is the answer.
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We know the rates here, they're given quite cleanly in the stem
A works at \(\frac{1}{n}\), B works at \(\frac{5}{n}\)

1) says A takes half the time B does for a junior order, so \(\frac{n}{2}\) mins
this tells us that the rate would be \(\frac{2}{n} = \frac{5}{m}\)
This is a clear relationship and we can conclude which is greater
SUFFICIENT

2) just says \(\frac{5}{m} > \frac{3}{2n}\)
or \(\frac{n}{m} > \frac{3}{10}\) (we can move things around worry free since everything here is positive)
Now, \(\frac{n}{m}\) could be \(\frac{4}{10}\), or it could be \(\frac{14}{10}\) (for example). Both tell a very different story
INSUFFICIENT
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