Last visit was: 23 Apr 2026, 17:28 It is currently 23 Apr 2026, 17:28
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
tejal777
Joined: 25 Oct 2008
Last visit: 09 Jan 2012
Posts: 360
Own Kudos:
6,991
 [42]
Given Kudos: 100
Location: Kolkata,India
Posts: 360
Kudos: 6,991
 [42]
3
Kudos
Add Kudos
38
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 23 Apr 2026
Posts: 109,785
Own Kudos:
Given Kudos: 105,853
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,785
Kudos: 810,870
 [11]
8
Kudos
Add Kudos
3
Bookmarks
Bookmark this Post
General Discussion
User avatar
Economist
Joined: 01 Apr 2008
Last visit: 24 Dec 2018
Posts: 383
Own Kudos:
Given Kudos: 18
Name: Ronak Amin
Schools: IIM Lucknow (IPMX) - Class of 2014
Schools: IIM Lucknow (IPMX) - Class of 2014
Posts: 383
Kudos: 4,504
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
maliyeci
Joined: 23 Jun 2009
Last visit: 04 Nov 2016
Posts: 200
Own Kudos:
250
 [1]
Given Kudos: 80
Location: Turkey
Concentration: Finance and Accounting
Schools:UPenn, UMich, HKS, UCB, Chicago
GMAT 2: 740 Q49 V41
Posts: 200
Kudos: 250
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Approach of economist is nice. Lets do it more mathematically.
1)insuff. No need to explain.
2)insuff. No need to explain.

together
line k=> y=mx+n
line j=> y=tx+y
we know from 1 that n is greater than y. And we know from 2 that they are intersecting at point (7,2).
That makes
2=7m+n
2=7t+y
7m+n=7t+y
7m+n<7t+n
7m<7t
m<t

SUFF.
C.
User avatar
mrsmarthi
Joined: 30 Nov 2008
Last visit: 09 Nov 2013
Posts: 335
Own Kudos:
Given Kudos: 15
Concentration: Finance, General Management
Schools:Fuqua
Posts: 335
Kudos: 1,892
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Maliyeci,

I have two questions -

In y = mx + b equation, m = slope and b is the Y intercept. From your represenation, how can we say that

maliyeci
we know from 1 that n is greater than y.

when variables n and y are the Y intercepts. Not X intercepts.

Can you please explain how you made this Inequality based on n > y(assuming y intercepts of L > y intercept of K). I am confused. :roll:

maliyeci
7m+n<7t+n
7m<7t
m<t
User avatar
maliyeci
Joined: 23 Jun 2009
Last visit: 04 Nov 2016
Posts: 200
Own Kudos:
250
 [1]
Given Kudos: 80
Location: Turkey
Concentration: Finance and Accounting
Schools:UPenn, UMich, HKS, UCB, Chicago
GMAT 2: 740 Q49 V41
Posts: 200
Kudos: 250
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
mrsmarthi
Maliyeci,

I have two questions -

In y = mx + b equation, m = slope and b is the Y intercept. From your represenation, how can we say that

maliyeci
we know from 1 that n is greater than y.

when variables n and y are the Y intercepts. Not X intercepts.

Can you please explain how you made this Inequality based on n > y(assuming y intercepts of L > y intercept of K). I am confused. :roll:

maliyeci
7m+n<7t+n
7m<7t
m<t
I beg your pardon for the intercepts. Yes you are rigth. I gave the Y intercept. The x intercepts are respectively;
-n/m and -y/t
But they are sufficient to find an answer.
That is the solution.
7m+n=2
n=2-7m
n/m=2/m-7
same as for the other
y/t=2/t-7
since -n/m is greater than -y/t; y/t is greater than n/m
so
2/m-7>2/t-7
2/m>2/t
so we can find the solution
C is suff.
User avatar
mrsmarthi
Joined: 30 Nov 2008
Last visit: 09 Nov 2013
Posts: 335
Own Kudos:
Given Kudos: 15
Concentration: Finance, General Management
Schools:Fuqua
Posts: 335
Kudos: 1,892
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Yes....this is correct. But with a small correction.

maliyeci
since -n/m is greater than -y/t; y/t is greater than n/m ==> n/m < y/t
so
2/m-7<2/t-7
2/m<2/t
so we can find the solution
C is suff.
User avatar
hgp2k
Joined: 18 Aug 2009
Last visit: 02 Nov 2022
Posts: 192
Own Kudos:
Given Kudos: 13
Posts: 192
Kudos: 794
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Sorry to disappoint you guys, but seems that the answer should be E.

First of all to solve this question think that the best way is graphic approach:

We all agree that (1) and (2) alone are not sufficient.

Lets combine --> draw only X-axis. k intercept is greater than j intercept --> k intercept (k1) point right to j intercept point (j1) --> Interception of lines is above X-axis (point 7;2) --> it will give us only three possible ways to draw the lines:
A. j has negative slope, k has negative slope --> slope of k>slope of j, (because j is closer to vertical line);
B. j has positive slope, k has negative slope --> slope of k<slope of j;
C. j has positive slope, k has positive slope --> slope of k>slope of j, (because k is closer to vertical line);

So (1)+(2) not sufficient. Answer E.

BUT the way you were solving also should get E:

f(k)=mx+n
f(j)=tx+p
(1) The x-intercept of line k is greater than the x-intercept of line j --> 0=mx+n; 0=tx+p --> -n/m>-p/t or
n/m<p/t --> not sufficient;
(2) Lines k and j intersect at (7, 2)
2=7m+n; 2=7t+p --> 7m+n=7t+p -->not sufficient;

Combining the way you did:
n=2-7m --> n/m=2/m-7
p=2-7t --> p/t=2/t-7
n/m<p/t --> 2/m-7<2/t-7 --> 1/m<1/t --> (t-m)/mt<0
And here is the catch, from above statement you can not determine whether m>t or not. t=1<m=3 statement is true and t=1>m=-3 statement is also true.
Answer E.

This exactly why I said IMO E :). Thanks for explanation Bunuel! :beer
User avatar
imhimanshu
Joined: 07 Sep 2010
Last visit: 08 Nov 2013
Posts: 216
Own Kudos:
Given Kudos: 136
GMAT 1: 650 Q49 V30
Posts: 216
Kudos: 6,365
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel


Lets combine --> draw only X-axis. k intercept is greater than j intercept --> k intercept (k1) point right to j intercept point (j1) --> Interception of lines is above X-axis (point 7;2) --> it will give us only three possible ways to draw the lines:
A. j has negative slope, k has negative slope --> slope of k>slope of j, (because j is closer to vertical line);
B. j has positive slope, k has negative slope --> slope of k<slope of j;
C. j has positive slope, k has positive slope --> slope of k>slope of j, (because k is closer to vertical line);


Hi Bunuel,

Request you to please look at the colored portion again and confirm if its correct. Isn't in Option A->Slope of j > Slope of K. If not, please provide your reasoning, may be I'm lacking some concept.

thanks
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 23 Apr 2026
Posts: 109,785
Own Kudos:
810,870
 [3]
Given Kudos: 105,853
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,785
Kudos: 810,870
 [3]
1
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
imhimanshu
Bunuel


Lets combine --> draw only X-axis. k intercept is greater than j intercept --> k intercept (k1) point right to j intercept point (j1) --> Interception of lines is above X-axis (point 7;2) --> it will give us only three possible ways to draw the lines:
A. j has negative slope, k has negative slope --> slope of k>slope of j, (because j is closer to vertical line);
B. j has positive slope, k has negative slope --> slope of k<slope of j;
C. j has positive slope, k has positive slope --> slope of k>slope of j, (because k is closer to vertical line);


Hi Bunuel,

Request you to please look at the colored portion again and confirm if its correct. Isn't in Option A->Slope of j > Slope of K. If not, please provide your reasoning, may be I'm lacking some concept.

thanks

A steeper incline indicates a higher absolute value of the slope.

So, if both lines have positive slope, then the line which is steeper has greater slope.
If both lines have negative slope, then the line which is steeper has greater absolute value slope, its slope is "more negative", so less than the slope of another line.

Similar questions to practice:
if-the-slopes-of-the-line-l1-and-l2-are-of-the-same-sign-is-126759.html
slopes-of-m-and-n-124025.html
line-n-and-p-lie-in-the-xy-plane-is-the-slope-of-the-line-30553.html
lines-n-and-p-lie-in-the-xy-plane-is-the-slope-of-line-n-97007.html
in-the-xy-plane-is-the-slope-of-line-l-greater-than-the-126941.html

Hope it helps.
User avatar
jlgdr
Joined: 06 Sep 2013
Last visit: 24 Jul 2015
Posts: 1,302
Own Kudos:
Given Kudos: 355
Concentration: Finance
Posts: 1,302
Kudos: 2,976
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I would solve algebraically.

Say line K is mx+b while like J is nx+c.

Question is is m>n?

Statement 1 tells us that -b/m>-c/n, but we know nothing about the signs of b and c hence insufficient.

Statement 2 says that 7m+b=7n+c, we could factorize to get m-n=c-b/7. Now question is is c-b>0? We don't know this.

Now from both statements together we still don't know whether c>b, so E is the best answer choice here.

Hope this gives a hand
Cheers!
J
User avatar
Lucky2783
Joined: 07 Aug 2011
Last visit: 08 May 2020
Posts: 415
Own Kudos:
Given Kudos: 75
Concentration: International Business, Technology
GMAT 1: 630 Q49 V27
GMAT 1: 630 Q49 V27
Posts: 415
Kudos: 2,109
Kudos
Add Kudos
Bookmarks
Bookmark this Post
tejal777
If lines k and j are in the xy–coordinate plane, is the slope of line k greater than the slope of line j ?

(1) The x-intercept of line k is greater than the x-intercept of line j
(2) Lines k and j intersect at (7, 2)

Answer: E

refer to images attached.
Attachments

srmt2.jpg
srmt2.jpg [ 48.18 KiB | Viewed 12818 times ]

stmt1.jpg
stmt1.jpg [ 45.94 KiB | Viewed 12749 times ]

User avatar
arnkaprx
Joined: 30 May 2023
Last visit: 29 Dec 2025
Posts: 6
Own Kudos:
Given Kudos: 97
Posts: 6
Kudos: 6
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Sorry to disappoint you guys, but seems that the answer should be E.

First of all to solve this question think that the best way is graphic approach:

We all agree that (1) and (2) alone are not sufficient.

Lets combine --> draw only X-axis. k intercept is greater than j intercept --> k intercept (k1) point right to j intercept point (j1) --> Interception of lines is above X-axis (point 7;2) --> it will give us only three possible ways to draw the lines:
A. j has negative slope, k has negative slope --> slope of k>slope of j, (because j is closer to vertical line);
B. j has positive slope, k has negative slope --> slope of k<slope of j;
C. j has positive slope, k has positive slope --> slope of k>slope of j, (because k is closer to vertical line);

So (1)+(2) not sufficient. Answer E.

BUT the way you were solving also should get E:


f(k)=mx+n
f(j)=tx+p
(1) The x-intercept of line k is greater than the x-intercept of line j --> 0=mx+n; 0=tx+p --> -n/m>-p/t or
n/m<p/t --> not sufficient;
(2) Lines k and j intersect at (7, 2)
2=7m+n; 2=7t+p --> 7m+n=7t+p -->not sufficient;

Combining the way you did:
n=2-7m --> n/m=2/m-7
p=2-7t --> p/t=2/t-7
n/m<p/t --> 2/m-7<2/t-7 --> 1/m<1/t --> (t-m)/mt<0
And here is the catch, from above statement you can not determine whether m>t or not. t=1<m=3 statement is true and t=1>m=-3 statement is also true.
Answer E.


Can't we also use the formula - m = y2-y1/x2-x1 here? By that we get slope for line k = 2-0/7-x1 and slope for line j is = 2-0/7-x2. And since (1) says that x2 > x1, we can say that m(j) < m(k)? And thus C.
avatar
Abolnasr
Joined: 10 Jul 2023
Last visit: 14 Aug 2024
Posts: 33
Own Kudos:
Given Kudos: 18
Posts: 33
Kudos: 9
Kudos
Add Kudos
Bookmarks
Bookmark this Post
This question is best approached by visually thinking about slope as if it's the physical steepness of a road, lines (roads) can fulfill both conditions with either one of them steeper than the other.
Moderators:
Math Expert
109785 posts
498 posts
212 posts