Last visit was: 18 Nov 2025, 22:25 It is currently 18 Nov 2025, 22:25
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
dreambeliever
Joined: 24 Nov 2010
Last visit: 20 Jun 2013
Posts: 118
Own Kudos:
291
 [51]
Given Kudos: 7
Location: United States (CA)
Concentration: Technology, Entrepreneurship
Posts: 118
Kudos: 291
 [51]
1
Kudos
Add Kudos
50
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 18 Nov 2025
Posts: 105,355
Own Kudos:
Given Kudos: 99,964
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,355
Kudos: 778,104
 [23]
10
Kudos
Add Kudos
13
Bookmarks
Bookmark this Post
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 18 Nov 2025
Posts: 105,355
Own Kudos:
778,104
 [9]
Given Kudos: 99,964
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,355
Kudos: 778,104
 [9]
2
Kudos
Add Kudos
7
Bookmarks
Bookmark this Post
General Discussion
User avatar
liftoff
Joined: 27 May 2010
Last visit: 27 Sep 2012
Posts: 59
Own Kudos:
16
 [3]
Given Kudos: 8
Status:Essaying
Location: Ghana
Concentration: Finance, Finance
Schools: Cambridge
GMAT 1: 690 Q47 V37
GPA: 3.9
WE:Accounting (Education)
Schools: Cambridge
GMAT 1: 690 Q47 V37
Posts: 59
Kudos: 16
 [3]
2
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
I would go with D.
We are already given one point at the point of intersection.
Statement 1 gives us an extra point therefore we can determine which line is steeper. sufficient
Statement 2 also gives us the same information. sufficient
User avatar
dreambeliever
Joined: 24 Nov 2010
Last visit: 20 Jun 2013
Posts: 118
Own Kudos:
Given Kudos: 7
Location: United States (CA)
Concentration: Technology, Entrepreneurship
Posts: 118
Kudos: 291
Kudos
Add Kudos
Bookmarks
Bookmark this Post
liftoff
I would go with D.
We are already given one point at the point of intersection.
Statement 1 gives us an extra point therefore we can determine which line is steeper. sufficient
Statement 2 also gives us the same information. sufficient

I was thinking if determining which one is steeper is enough or not.

Per (1) The x-intercept of line m is greater than the x-intercept of line n.

so line m can have a slope of lets say -2. If line n also has a -ve slope then it will need to be 'flatter' than line m for its x intercept to be greater than that of line m. So its slope will need to be > -2 (for -ve slopes flatter line are closer to 0 that slopes of steeper lines). so in this case slope of line n can be something like -1. So slope of n > slope of m (-1>-2).
however, if slope of m is lets say 2, slope of n can be -ve like -2 with a greater x intercept. This satisfies the condition 1, but slope of m> slope of n in this case (2>-2).
Hence, (1) is insufficient.

Similarly we can prove for the y intercept in case of 2nd statement.

The 2 statements taken together, they should still be insufficient.

OA is D. But i'm having trouble understanding it.

Can someone please explain if I'm wrong?
User avatar
ronr34
Joined: 08 Apr 2012
Last visit: 10 Oct 2014
Posts: 248
Own Kudos:
Given Kudos: 58
Posts: 248
Kudos: 250
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I have seen a lot of examples of this question, and every time it comes down to the Y intercept.
Can we use this as a shortcut? can we make a generalization here?
User avatar
jlgdr
Joined: 06 Sep 2013
Last visit: 24 Jul 2015
Posts: 1,311
Own Kudos:
2,863
 [4]
Given Kudos: 355
Concentration: Finance
Posts: 1,311
Kudos: 2,863
 [4]
2
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
ronr34
Bunuel
Bumping for review and further discussion.
I have seen a lot of examples of this question, and every time it comes down to the Y intercept.
Can we use this as a shortcut? can we make a generalization here?

Yes we can use something else other than the graph method, which I find a little bit difficult to follow on many cases.

Let's see we need to know if m>n or if m-n>0, 'm and 'n' being the slopes of the respective lines

We know that they intersect at point (-2,4)

Then we have Line m= y = mx + b ---> 4 = -2m +b
Line n = y = nx+c---> 4=-2n+c

Both equal, -2n+c= -2m+b
2m-2n = b-c
m-n = (b-c)/2

Now going back to the question.

Is b-c/2 > 0?

is b-c>0, is b-c?

Statement 1

We are given that -b/m>-c/n
-bn>-cm

We can't tell whether b>c
Insuff

Statement 2

This is exactly what we were looking for
b>c

Sufficient

B stands

Hope its clear
Cheers!
J :)

YES YOU CAN
avatar
guimooow
Joined: 13 Dec 2013
Last visit: 18 Mar 2014
Posts: 4
Own Kudos:
6
 [1]
Given Kudos: 26
Posts: 4
Kudos: 6
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
amaxing Jlgdr!! thank you buddy. it is so clear now
User avatar
musunna
Joined: 14 Sep 2013
Last visit: 12 May 2020
Posts: 88
Own Kudos:
Given Kudos: 38
Status:Just redeemed Kudos for GMAT Club Test !!
Location: Bangladesh
GMAT 1: 530 Q40 V23
GPA: 3.56
WE:Analyst (Commercial Banking)
GMAT 1: 530 Q40 V23
Posts: 88
Kudos: 55
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel


(1) The x-intercept of line m is greater than the x-intercept of line n --> \(-\frac{b}{m}>-\frac{c}{n}\)

hi Bunuel, I'm not sure how can we come to this equation mentioned above. Would you please explain a bit on this ?
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 18 Nov 2025
Posts: 105,355
Own Kudos:
778,104
 [1]
Given Kudos: 99,964
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,355
Kudos: 778,104
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
musunna
Bunuel


(1) The x-intercept of line m is greater than the x-intercept of line n --> \(-\frac{b}{m}>-\frac{c}{n}\)

hi Bunuel, I'm not sure how can we come to this equation mentioned above. Would you please explain a bit on this ?

I think this is explained here: slopes-of-m-and-n-124025.html#p1029568

Equation of a line in point intercept form is \(y=mx+b\), where: \(m\) is the slope of the line, \(b\) is the y-intercept of the line (the value of \(y\) for \(x=0\)),\(-\frac{b}{m}\) is the x-intercept of the line (the value of \(x\) for \(y=0\)). (Check Coordinate Geometry chapter of Math Book for more on this topic: math-coordinate-geometry-87652.html)
avatar
02999
Joined: 09 Apr 2020
Last visit: 06 May 2023
Posts: 20
Own Kudos:
Given Kudos: 516
Posts: 20
Kudos: 3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
karthiksms
could someone pl explain ? i'm unable to understand answer.

ALGEBRAIC WAY:
Lines m and n lie in the xy-plane and intersect at the point (-2; 4). Is the slope of line m less than the slope of line n?

Equation of a line in point intercept form is \(y=mx+b\), where: \(m\) is the slope of the line, \(b\) is the y-intercept of the line (the value of \(y\) for \(x=0\)), \(-\frac{b}{m}\) is the x-intercept of the line (the value of \(x\) for \(y=0\)). (Check Coordinate Geometry chapter of Math Book for more on this topic: https://gmatclub.com/forum/math-coordina ... 87652.html)

We are given two lines: \(y_m=mx+b\) and \(y_n=nx+c\). Now, as they intersect at the point (-2; 4) then: \(4=-2m+b\) and \(4=-2n+c\) (this point is common for both of the lines) --> \(b=4+2m\) and \(c=4+2n\).

Question: is \(m<n\)?

(1) The x-intercept of line m is greater than the x-intercept of line n --> \(-\frac{b}{m}>-\frac{c}{n}\) --> \(-\frac{4+2m}{m}>-\frac{4+2n}{n}\) --> \(\frac{1}{n}-\frac{1}{m}>0\) --> insufficient to answer whether \(m<n\): if \(n=2\) and \(m=-4\) then YES but if \(n=2\) and \(m=4\) then NO. Not sufficient.

(2) The y-intercept of line n is greater than the y-intercept of line m --> \(c>b\) --> \(4+2n>4+2m\) --> \(n>m\). Sufficient.

Answer: B.

why can't we deduce like below -
1/n-1/m >0=> 1/n>1/m=> m>n

Can you please explain.
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 18 Nov 2025
Posts: 105,355
Own Kudos:
778,104
 [1]
Given Kudos: 99,964
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,355
Kudos: 778,104
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
02999
Bunuel
karthiksms
could someone pl explain ? i'm unable to understand answer.

ALGEBRAIC WAY:
Lines m and n lie in the xy-plane and intersect at the point (-2; 4). Is the slope of line m less than the slope of line n?

Equation of a line in point intercept form is \(y=mx+b\), where: \(m\) is the slope of the line, \(b\) is the y-intercept of the line (the value of \(y\) for \(x=0\)), \(-\frac{b}{m}\) is the x-intercept of the line (the value of \(x\) for \(y=0\)). (Check Coordinate Geometry chapter of Math Book for more on this topic: https://gmatclub.com/forum/math-coordina ... 87652.html)

We are given two lines: \(y_m=mx+b\) and \(y_n=nx+c\). Now, as they intersect at the point (-2; 4) then: \(4=-2m+b\) and \(4=-2n+c\) (this point is common for both of the lines) --> \(b=4+2m\) and \(c=4+2n\).

Question: is \(m<n\)?

(1) The x-intercept of line m is greater than the x-intercept of line n --> \(-\frac{b}{m}>-\frac{c}{n}\) --> \(-\frac{4+2m}{m}>-\frac{4+2n}{n}\) --> \(\frac{1}{n}-\frac{1}{m}>0\) --> insufficient to answer whether \(m<n\): if \(n=2\) and \(m=-4\) then YES but if \(n=2\) and \(m=4\) then NO. Not sufficient.

(2) The y-intercept of line n is greater than the y-intercept of line m --> \(c>b\) --> \(4+2n>4+2m\) --> \(n>m\). Sufficient.

Answer: B.

why can't we deduce like below -
1/n-1/m >0=> 1/n>1/m=> m>n

Can you please explain.

You cannot cross-multiply 1/n > 1/m to get m > n because we don't know the signs of m and n. If they have the same sign, then yes, after cross-multiplying we get m > n but if n is positive and m is negative, then after cross-multiplying we get m < n. For example:

If n = 2 and m = 3 --> 1/2 > 1/3 --> 3 > 2;
If n = -3 and m = -2 -->1/(-3) > 1/(-2) --> -2 > -3.

But if n = 2 and m = -2 -->1/2 > 1/(-2) --> -2 < 2.
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,583
Own Kudos:
Posts: 38,583
Kudos: 1,079
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Moderators:
Math Expert
105355 posts
496 posts