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23 Feb 2021, 17:09
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Hi Everyone!
I'm new to the club. If anyone can assist me with this problem, I would be very appreciated
The topic is about Combination. Why is that 10C4 = 10C6? I understand that if we select a group of r from a pool event, we automatically create another group of (n-r) folks who were left behind. So every group of 4 corresponds to a group of 6. But if we calculate it, 10C4 = 10*9*8*7/4*3*2*1. On the other hand, 10C6 = 10*9*8*7/6*5*4*3*2*1. How is this equal to 10C4? Can someone please clarify?
Thank you
I'm new to the club. If anyone can assist me with this problem, I would be very appreciated
The topic is about Combination. Why is that 10C4 = 10C6? I understand that if we select a group of r from a pool event, we automatically create another group of (n-r) folks who were left behind. So every group of 4 corresponds to a group of 6. But if we calculate it, 10C4 = 10*9*8*7/4*3*2*1. On the other hand, 10C6 = 10*9*8*7/6*5*4*3*2*1. How is this equal to 10C4? Can someone please clarify?
Thank you
24 Feb 2021, 10:56
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\(^nC_r = \frac{n!}{r!(n-r)!}\)
\(^{10}C_4 = \frac{10!}{6!4!}\)
\(^{10}C_6 = \frac{10!}{6!4!}\)
\(^{10}C_4 = \frac{10!}{6!4!}\)
\(^{10}C_6 = \frac{10!}{6!4!}\)
Angiee1112
25 Feb 2021, 08:01
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Angiee1112
10C4 is not equal to 10*9*8*7/4*3*2*1.
10C4 = (10*9*8*7)/[(4*3*2*1)(6*5*4*3*2*1)]
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