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06 Oct 2011, 03:38
Kudos
Bookmarks
A cylinder tank with radius of the base 1 and height 2 is half full of water. If all the water is poured into another cylinder tank with height 1 and radius of the base 2, to what percent of its capacity will this new tank be filled?
(C) 2008 GMAT Club - [t]m25#37[/t]
(A) 20%
(B) 25%
(C) 32%
(D) 35%
(E) 40%
(C) 2008 GMAT Club - [t]m25#37[/t]
(A) 20%
(B) 25%
(C) 32%
(D) 35%
(E) 40%
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06 Oct 2011, 04:19
Kudos
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kkalyan
Volume of a cylinder= \(\pi*r^2*h\)
Volume of a cylinder 1= \(\pi*(1)^2*2=2 \pi\). Since the tank is half filled, Volume of water=\(\frac{2 \pi}{2}=\pi\)
Volume of a cylinder 2= \(\pi*(2)^2*1=4 \pi\)
% of water in 2= [(Volume of water)/(Volume of a cylinder 2)]*100
% of water in 2 \(=\frac{\pi}{4 \pi}*100=25%\)
Ans: "B"
06 Oct 2011, 07:27
Kudos
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vol of cylinder1 = \(\pi*r^2h = 2\pi\)
vol of cylinder2 = \(\pi*r^2h = 4\pi\)
vol of cyl2 is twice that of cyl1. so if cyl1 is 1/2 filled then cyl2 must be \(\frac{1}{4}\) filled i.e. 25%
vol of cylinder2 = \(\pi*r^2h = 4\pi\)
vol of cyl2 is twice that of cyl1. so if cyl1 is 1/2 filled then cyl2 must be \(\frac{1}{4}\) filled i.e. 25%
