Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
May 0111:00 AM PDT
-12:00 PM PDT
Free- full-length test + 15 concept videos + 150+ short videos + study plan!
May 0312:30 AM EDT
-01:30 AM EDT
Learn how Kamakshi achieved a GMAT 675 with an impressive 96th %ile in Data Insights. Discover the unique methods and exam strategies that helped her excel in DI along with other sections for a balanced and high score.
16 Sep 2014, 01:10
Kudos
Bookmarks
Is the perimeter of a rectangle greater than 8 inches?
(1) The diagonal of the rectangle is twice as long as its shorter side
(2) The diagonal of the rectangle is 4 inches longer than its shorter side
(1) The diagonal of the rectangle is twice as long as its shorter side
(2) The diagonal of the rectangle is 4 inches longer than its shorter side
16 Sep 2014, 01:10
Kudos
Bookmarks
Official Solution:
Is the perimeter of a rectangle greater than 8 inches?
The question asks whether \(Perimeter=2(a+b) \gt 8\), or whether \(a+b \gt 4\), (where \(a\) and \(b\) are the lengths of the sides of the rectangle).
(1) The diagonal of the rectangle is twice as long as its shorter side.
Clearly insufficient, we know the shape of the rectangle but not its size.
(2) The diagonal of the rectangle is 4 inches longer than its shorter side.
This statement basically says that the length of the diagonal is greater than 4 inches: \(d \gt 4\). Now, consider the triangle made by the diagonal and the two sides of the rectangle: since the length of any side of a triangle must be smaller than the sum of the other two sides, then we have that \(a+b \gt d\), so \(a+b \gt d \gt 4\). Sufficient.
Answer: B
Is the perimeter of a rectangle greater than 8 inches?
The question asks whether \(Perimeter=2(a+b) \gt 8\), or whether \(a+b \gt 4\), (where \(a\) and \(b\) are the lengths of the sides of the rectangle).
(1) The diagonal of the rectangle is twice as long as its shorter side.
Clearly insufficient, we know the shape of the rectangle but not its size.
(2) The diagonal of the rectangle is 4 inches longer than its shorter side.
This statement basically says that the length of the diagonal is greater than 4 inches: \(d \gt 4\). Now, consider the triangle made by the diagonal and the two sides of the rectangle: since the length of any side of a triangle must be smaller than the sum of the other two sides, then we have that \(a+b \gt d\), so \(a+b \gt d \gt 4\). Sufficient.
Answer: B
General Discussion
06 Sep 2015, 10:54
Kudos
Bookmarks
I think this is a high-quality question and I agree with explanation.
