M15#29

Question

If in a six-digit integer  N ,  F(k)  is the value of the  k-th  digit, is  N  divisible by 7 (For example,  F(4)  is the value of the hundreds digit of  N  )?

(1)  F(1) = F(4), F(2) = F(5), F(3) = F(6) 
(2)  F(1) = F(2) = ... = F(6)

SOLUTION:
 Statements (1) and (2) by themselves are sufficient. S1 tells us that the last three digits of  N  are the same as the first three digits:  N = abcabc  . Note that  N = abc*1000 + abc = abc*1001  . As 1001 is divisible by 7,  N  is also divisible by 7.
The correct answer is D.

powerka · Answer

I believe there is an error in this question.

If, as it says, F(4) is the value of the hundreds digit, then F(1) is the value of the decimal digit of N.

Given that N is an integer, then F(1)=0.

F(1)=F(2)=F(3)=F(4)=F(5)=F(6)=0 --> N=0 and it is not a 6 digit integer. This contradicts the question stem.

Or am I missing something?

diddygmat · Answer

This question somehow doesnt make sense. How can F(4) be hundreds digit? shouldnt it 1000's digit..

Help will be really appreciated!
Thanks!

kapilhede17 · Answer

Can some one comment here , Since this figures in the gmatclub tests ?

PathFinder007 · Answer

Hi Bunnel,

I also have a doubt here. if f(4) is hundreads digit as given in question then how f(1) can be units digit.

Please provide your comments on this.

Thanks.

Bunuel · Answer

F(1) is the value of HUNDRED THOUSANDS digit not the UNITS digit.

123,456
1 - HUNDRED THOUSANDS
2 - TEN THOUSANDS
3 - THOUSANDS
4 - HUNDREDS
5 - TENS
6 - UNITS

Hope it's clear.

M15#29

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