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praveen_rao7
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"E"....

48(XM/XM) can be 48 or undefined i.e. if XM = 0
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MA
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praveen_rao7
What is the product of A & B?
A = 2/xm
B =24xm

another nice question and agree with E.
x and m could be 0 or anything other than 0.
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praveen_rao7
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This question is from Challenge 2, OA says it is C. I picked E too. OA must be wrong
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I would say C.

The reason beeing :
if A has a solution which is : 2/xm , then xm cant be 0.
we should not consider xm = 0 as a possible if A has such solution.

Let s not be trickier than GMAT
therefore C may be the answer
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praveen_rao7
This question is from Challenge 2, OA says it is C. I picked E too. OA must be wrong


what's the OE Praveen ? I wud agree with "C" if it had said that A and B are real numbers.
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it says A = 2/xm so ixm cannot be zero..
therefore, C is the answer.
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Problem is we don't know any info on A or B, they could be imaginary

I don't quite agree with OA C

I guess I am not sure if such controversial problems appear in GMAT
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First, GMAT does not deal with imaginary numbers so we must assume that A and B are real numbers. Second, IIRC a number divided by zero does not yield imaginary numbers.

If I were to do this question, I would assume that A is a real number (instead of undefined). The answer thus would be C. In real GMAT test, I wouldn't be surprised if it specifies that x and m are not zero, or A and B are real, though this would make this question very easy.
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The answer C IS Correct.
Here's why
A => 2/xm
B => 24xm (NOT 24/xm)

A* B => 2/xm *24xm => 48
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vprabhala
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i agree either this question will be made easier on GMAT (if it appears ) or we can assume that A and B are real..
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Honghu, you are right, I ment undefined & not imaginary. May be we should just correct this problem in challenge 5 to avoid such confusion. I doubt ETS would get into controversy like this.



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