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students of class are made to stand in row if one student is extra in a row there would be 2 rows less if one student is less in row there would be 3 rows more find the no of student

a.120
b.90
c.60
d.30
e.cant find

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R = titles of Robert
D = titles of David
\(3*(R-15)=D+15\)
\(D-15=R+15\)

You solve this and obtain \(R=45\) and \(D=75\), it's not B and here we can see why:

b.\(R=60\) so \(3*(60-15)=D+15\) \(D=120\), then the second equation doesn't "work"
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Salary = exp + savings

\(\frac{eH+sH}{eK+sK}=\frac{9}{7}\) saving are 200$ \(\frac{eH+200}{eK+200}=\frac{9}{7}\)
\(\frac{eH}{eK}=\frac{4}{3}\)

\(7(eH+200)=9(eK+200)\) \(7eH-9eK=400\)
\(3eH=4eK\)
do some math... :?

eH=1600 and eK=1200
\(SalaryKime = 1200+200 = 1400\)$ B and not C...
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M = rate of work of men
b = rate of work of boys

\((4M+6B)*20 days= 1 job\)
\((3M+4B)*28 = 1 job\)

\(80M+120B=1\)
\(84M+112B=1\) so dome math...

\(M=\frac{1}{140}\)
\(B=\frac{1}{280}\) those are the rate of work (each hour).

\(7 boys = 7*\frac{1}{128}=\frac{7}{128}\) each hour
To complete one job 1 \(job = time*\frac{7}{280}\) now this time is \(\frac{280}{7}\) hour that is none of your answers
If the question were about men
\(7 men = 7*\frac{1}{140}=\frac{7}{140}\)
To complete one job 1 \(job = time*\frac{7}{140}\) now this time is \(\frac{140}{7}\) = 20 A
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IMO C
lets put that in equation.
No. of students in one row=x
No. of rows=y
Total students=xy.
1st equation:
(x+1)(y-2)=xy i.e. xy-2x+y-2 =xy i.e. -2x+y=2
2nd Equation
(x-1)(y+3)=xy i.e. xy+3x-y-3 =xy i.e. 3x-y=3

adding 1st and second equation we get x=5
putting x=5 in any of the equation we get y=12

so total number of Students should be xy = 5*12 = 60

R u sure OA is D?
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robert has 45 tiles.. agree with zar
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abhishek1990p
students of class are made to stand in row if one student is extra in a row there would be 2 rows less if one student is less in row there would be 3 rows more find the no of student

a.120
b.90
c.60
d.30
e.cant find

Think of the students standing in a matrix of rows and columns.

There are r rows and c columns. So there are a total of rc students.

Algebra approach:

Now if there is 1 student extra in each row i.e. there is one column extra, no of rows will be r-2 rows.
If there is 1 student less in each row, i.e. there is one column less, no of rows will be r+3 rows.

(r - 2)(c + 1) = rc
(r + 3)(c - 1) = rc

r - 2c = 2
-r + 3c = 3

c = 5
r = 12

Total number of students = 5*12 = 60
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4men and 6 boys can finish a piece of work in 20 days while 3 men and 4 boys can finish it in 28 days find the time taken by 7 men to finish the work

a.20 days
b.40 days
c.140 days
d.280 days
e. cant find


M = rate of work of each man, B - rate of work of each boy
4M + 6B = 1/20
3M + 4B = 1/28

Solve simultaneously. We need to get rid of B so multiply first equation by 2 and the second one by 3

8M + 12B = 1/10
9M + 12B = 3/28

Subtract the equations to get:
M = 2/280 = 1/140 = Rate of work of one man

Rate of work of 7 Men = 7/140 = 1/20
Time taken = 1/Rate of work = 20 days
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There are two buses. If 10 passenger are sent from the first bus to second bus, passenger in both will be equal. If 20 passenger from 2nd bus are sent to 1st bus, the number of passenger in first will be twice the number of passenger of 2nd
Find total passenger

a.180
b.500
c.600
d.300
e100
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5.the area of rectangle increase by 200 sqmtr if lenghth is increse by 8m and breadth by 3m the area incre by 225sq m if lenght is incr by 3 m and bradth by 8m find perimeter
a.74m
b.60m
c.56m
d.48m
e.44m
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6.the charges for a 5 day trip by tourisim bus for one full and half ticket is 1440 iccluding of boarding charges which are same for a full as well as a half ticket
the charges for the same trip for 2 full and one half ticket the charges are 2220the fare for half ticket is 75% of the full ticket find the difference betwn the fare and boarding charges for one full ticket
a.480
b.360
c.300
d.240
e.180
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After covering a distance of 30 miles with a uniform speed, a train engine develops a defect and consequently its speed is reduced to 4/5th of its original speed. In result the train reaching its destination late by 3/4 hrs. Had it happened after covering 18 miles more the train would have reached its destination 9 mins earlier.
Find the distance of journey

a.75 miles
b.90 miles
c.105 miles
d.120 miles
e.135 miles
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Albert invested a some amount at rate of 3% per quaterly simple interest and other amount at the rate of 7.5% half yearly simple interest. he received 1500$ as interest for a year. if he had interchanged the amount invested he would have received 78$ more as interest for the year.
Find the smallest investment

a.7062.5$
b.5762.5$
c.7562.5$
d.5002.0$
e.7002.0$
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A man sold a strawberry juice can and pineapple juice can for 760$ therby making profit of 25%on strawberry juice can and 10% on pineapple juice can by selling for 767.50$ he would have realized a profit of 10% on strawbeery can and 25% on pineapple can
Find the cost price of pineapple juice can

a.175$
b.210$
c.240$
d.300$
e.350$
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A child on a controlled diet is fed 300 ounce of a mixture of two foods a and b food a contains 10% protein and food b contains 15% protein if child diet contains exactly 38 ounce of protein daily.
How many ounce of food a are in the mixture?

a.100
b.140
c.150
d.160
e.200
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F=first bus
S=second bud

\(F-10=S+10\)
\(2*(S-20)=F+20\) \(2S-40=F+20\) \(2S-F=60\) do some annoying math

\(F=100, S=80\)

A
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11.A train covered a certain distance at uniform speed if train would have been 6miles/hour faster it would have taken 4 hrs less than the scheduled time and if the train were slower by 6 miles/hour it would have taken 6 hrs more than the scheduled time
find the distance in miles of journey
a.840
b.780
c.720
d.680
e.630
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