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01 Aug 2003, 04:35
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A ceratin safe has a secret lock consisting to 3 rolling disks; the first being marked 0-9; the second 0-1; the third 0-9 again. John does not know the right code but wants to have the safe open. What is the probability that he will not open it?
(1) 1/200
(2) 1/1000
(3) 999/1000
(4) 199/200
(5) 1/3
(1) 1/200
(2) 1/1000
(3) 999/1000
(4) 199/200
(5) 1/3
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01 Aug 2003, 06:40
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stolyar
(4) 199/200 - 10 values for first times 2 for second times 10 for third. = 200. 1 chance out of 200 to open it, means 199/200 to not open it.
Another way to solve this problem would be to just rearrange the order of the dials. Put the 2nd one first, then you're looking at possible values of 0-199 inclusive. Or 200 different numbers.
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Hi there,
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