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06 Jan 2021, 09:04
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
58% (01:48) correct
42%
(02:15)
wrong
based on 153
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On the xy-coordinate plane, all of the following xy-coordinate points lie on the circumference of a circle whose radius is 10 and whose center lies at the (x,y) point (-1,0) EXCEPT:
A. \((–6, –7)\)
B. \((–2, 3\sqrt{11})\)
C. \((–1, –10)\)
D. \((7, 6)\)
E. \((1, -4\sqrt{6})\)
A. \((–6, –7)\)
B. \((–2, 3\sqrt{11})\)
C. \((–1, –10)\)
D. \((7, 6)\)
E. \((1, -4\sqrt{6})\)
06 Jan 2021, 14:29
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For points of the circumference, Distance from center (-1,0)= radius = 10
A. (–6,–7) -> Sqrt (25+49) not equal to 10
B. (–2,3√11) -> Sqrt (1+99) = radius
C. (–1,–10) -> Sqrt (0+100) = radius
D. (7,6) -> Sqrt (64+36) = radius
E. (1,−4√6) -> Sqrt(4 +96)= Radius.
So, I think A.
A. (–6,–7) -> Sqrt (25+49) not equal to 10
B. (–2,3√11) -> Sqrt (1+99) = radius
C. (–1,–10) -> Sqrt (0+100) = radius
D. (7,6) -> Sqrt (64+36) = radius
E. (1,−4√6) -> Sqrt(4 +96)= Radius.
So, I think A.
07 Jan 2021, 08:29
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Bunuel
The first point gives us the radius would be \(\sqrt{(-1 + 6)^2 + 7^2} = \sqrt{5^2 + 7^2}\) which is not 10, so A is the answer. To get the radius of 10 from integers we need either a difference of (0, 10) or (6, 8).
Ans: A
