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trickygmat
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In the xy plane , point (r,s) lies on the circle with center 17 Oct 2005, 07:48
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In the xy plane , point (r,s) lies on the circle with center at the origin. What is the value of r^2 + s^2.
1) the circle has the radius 2.
2) The point (v2, -v2) lies on the circle.



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In the xy plane , point (r,s) lies on the circle with center 17 Oct 2005, 08:12
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Answer is: A

The point lies on the circle. Hence a straight drawn up/down (or) left or right would interesect x or y axis. A straight line drawn from (r,s) to origin would then form a triangle (right angled triangle).

Given the above, r^2 + s^2 = hypotenuse^2 (here hypotenuse is nothing but radius)
= 2^2
= 4

Stmt#2. V2 is unknown, hence insufficient (Am I missing anything here?)

Whats OA?
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Antmavel
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In the xy plane , point (r,s) lies on the circle with center 17 Oct 2005, 09:11
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I think there was a mistake. I've already seen this post and this problem.
Statement 2 is different from this stem :
(2) The point (square root(2), -square root(2)) lies on the circle.

OA is D

1st statement -> sudhagar explained it well. Check it.

2nd statement -> you can find the radius because you get the radius from it
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In the xy plane , point (r,s) lies on the circle with center 17 Oct 2005, 11:36
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How do you get the radius if you have been given statement 2.

i mean i know its simple but I have just started studying for GMAT and seem to be a bit out of touch.
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gsr
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In the xy plane , point (r,s) lies on the circle with center 17 Oct 2005, 11:46
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eaqn of the circle is s^2+r^2 = radius^2
A) Using A we can find radius^2 (explained in above posts)
B) Since the circle has the origin (0,0) as center and passes thru (2,-2), we can find the radius - distance from the center to the given point. This is the radius. So this is also sufficient to ans. the Q

So D

If it is really (v2, -v2) -> then answer is A!



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