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Apples' price consist a basic cost for a basic amount plus an additional cost for each pound thereafter. If 5 pounds apple cost $6, how much did 15 pounds cost?
1). Cost on 8 pounds is $1.5 more than that on 5 pounds.
2). Cost on 10 pounds is $1 more than that on 8 pounds.
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Apples' price consist a basic cost for a basic amount plus an additional cost for each pound thereafter. If 5 pounds apple cost $6, how much did 15 pounds cost? 1). Cost on 8 pounds is $1.5 more than that on 5 pounds. 2). Cost on 10 pounds is $1 more than that on 8 pounds.
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from i, Given that cost (5 lb) = $6.00 and we also know that the cost of 8 lb = cost (5 lb) + $1.5, we can answer the question.
Apples' price consist a basic cost for a basic amount plus an additional cost for each pound thereafter. If 5 pounds apple cost $6, how much did 15 pounds cost? 1). Cost on 8 pounds is $1.5 more than that on 5 pounds. 2). Cost on 10 pounds is $1 more than that on 8 pounds.
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$6 = nx + (5-n)y
where n is basic no of lbs
x is amount for n no of lbs
(5-n) is remaining lbs
y is charge for remaining lbs.
Using 1) $7.5 = nx + (8-n)y
We can solve for y but not the remaining.
Using 2) we cannot solve for n,x etc
Using both, again not possible.
Apples' price consist a basic cost for a basic amount plus an additional cost for each pound thereafter. If 5 pounds apple cost $6, how much did 15 pounds cost? 1). Cost on 8 pounds is $1.5 more than that on 5 pounds. 2). Cost on 10 pounds is $1 more than that on 8 pounds.
$6 = nx + (5-n)y where n is basic no of lbs x is amount for n no of lbs (5-n) is remaining lbs y is charge for remaining lbs.
Using 1) $7.5 = nx + (8-n)y We can solve for y but not the remaining. Using 2) we cannot solve for n,x etc Using both, again not possible.
Hence E.
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Your objective is to find y and that you can.
then just add 10y to the cost of 5 lb - to answer the question
Apples' price consist a basic cost for a basic amount plus an additional cost for each pound thereafter. If 5 pounds apple cost $6, how much did 15 pounds cost? 1). Cost on 8 pounds is $1.5 more than that on 5 pounds. 2). Cost on 10 pounds is $1 more than that on 8 pounds.
$6 = nx + (5-n)y where n is basic no of lbs x is amount for n no of lbs (5-n) is remaining lbs y is charge for remaining lbs.
Using 1) $7.5 = nx + (8-n)y We can solve for y but not the remaining. Using 2) we cannot solve for n,x etc Using both, again not possible.
Hence E.
Your objective is to find y and that you can. then just add 10y to the cost of 5 lb - to answer the question
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But the question says price consists a basic cost for a basic amount. But we dont know what that basic amount is. How can you assume that it is 5?
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.