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Many thanks. You have got it right.
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gsaxena26
In a survey of 248 people, 156 are married, 70 are self-employed and 25% of those who are married are self-employed. If a person is to be randomly selected from those surveyed, what is the probability that the person selected will be self-employed but not married?

A. 1/8
B. 4/31
C. 117/248
D. 1/4
E. 31/117
Attachment:
tableprob.png
tableprob.png [ 8.93 KiB | Viewed 16654 times ]
A double matrix works well here.
The calculations are simple and few, but the categories are easier to see in a matrix.

Total: 248 people
Married: 156
Self-employed: 70

1) 25 percent of those who are married are self-employed:

\(\frac{1}{4}\) * 156 = 39

2) Self-employed but not married:

(70 - 39) = 31

3) Probability that a randomly selected person from all 248 will be self-employed but not married (31):

\(\frac{31}{248} = \frac{1}{8}\)

Answer A
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gsaxena26
In a survey of 248 people, 156 are married, 70 are self-employed and 25% of those who are married are self-employed. If a person is to be randomly selected from those surveyed, what is the probability that the person selected will be self-employed but not married?

A. 1/8
B. 4/31
C. 117/248
D. 1/4
E. 31/117


hi
both self employed and married
= 156 * (25/100) = 39

only self employed = 70 - 39 = 31
probability:

only self employed / total
= 31 / 248
= 1/8

thanks
cheers through the kudos button if this helps
:cool:
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­Straightforward overlapping sets problem:

­
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