Last visit was: 25 Apr 2026, 17:21 It is currently 25 Apr 2026, 17:21
Home
Messages
Tests
Schools
Events
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
User avatar
Juaz
User avatar
Joined: 18 Jul 2006
Last visit: 06 Oct 2008
Posts: 241
Own Kudos:
308
Posts: 241
Kudos: 308
Mike and Ted are among the nine players a basketball coach 08 May 2007, 02:18
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Mike and Ted are among the nine players a basketball coach can choose from to field a five-player team. If all five players are chosen at random, what is the probability of choosing a team that includes Mike and Ted?


1/9
1/6
2/9
5/18
1/3



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
User avatar
demmy
User avatar
Joined: 24 Aug 2007
Last visit: 19 Sep 2007
Posts: 9
Posts: 9
Kudos: 0
Mike and Ted are among the nine players a basketball coach 13 Sep 2007, 12:33
Kudos
Add Kudos
Bookmarks
Bookmark this Post
[/quote]

How do you come up with 7c3
User avatar
KillerSquirrel
User avatar
Joined: 08 Jun 2005
Last visit: 28 Mar 2009
Posts: 520
Own Kudos:
647
Posts: 520
Kudos: 647
Mike and Ted are among the nine players a basketball coach 13 Sep 2007, 12:56
Kudos
Add Kudos
Bookmarks
Bookmark this Post
9C5 = 126 ---> choosing five items out of nine.

7C3 = 35 ---> choosing three items out of seven.

the logic is simple:

since two items have to be in the team (i.e probability = 1) then we only have to find the probability of the other three items (i.e 7C3)

1*7C3/9C5 = 35/126 = 5/18

:)
User avatar
demmy
User avatar
Joined: 24 Aug 2007
Last visit: 19 Sep 2007
Posts: 9
Posts: 9
Kudos: 0
Mike and Ted are among the nine players a basketball coach 13 Sep 2007, 13:17
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Actually .. I don't follow. Can you please re-iterate that.


Thx
User avatar
KillerSquirrel
User avatar
Joined: 08 Jun 2005
Last visit: 28 Mar 2009
Posts: 520
Own Kudos:
647
Posts: 520
Kudos: 647
Mike and Ted are among the nine players a basketball coach 13 Sep 2007, 13:44
Kudos
Add Kudos
Bookmarks
Bookmark this Post
demmy
Actually .. I don't follow. Can you please re-iterate that.


Thx
Show more


Can you please write what do you find the hardest to understand - so I can focus my explanation.

Thanks

:)
User avatar
demmy
User avatar
Joined: 24 Aug 2007
Last visit: 19 Sep 2007
Posts: 9
Posts: 9
Kudos: 0
Mike and Ted are among the nine players a basketball coach 13 Sep 2007, 13:50
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Just how you get the 7C3. 9C5 I understand. Many thanks.
User avatar
KillerSquirrel
User avatar
Joined: 08 Jun 2005
Last visit: 28 Mar 2009
Posts: 520
Own Kudos:
647
Posts: 520
Kudos: 647
Mike and Ted are among the nine players a basketball coach Updated on: 13 Sep 2007, 14:11
Originally posted by KillerSquirrel on 13 Sep 2007, 14:05.
Last edited by KillerSquirrel on 13 Sep 2007, 14:11, edited 1 time in total.
Kudos
Add Kudos
Bookmarks
Bookmark this Post
demmy
Just how you get the 7C3. 9C5 I understand. Many thanks.
Show more


You need to choose five players out of nine. But two of those players are already known to be Mike and Ted, so the probability of choosing Mike and Ted is 100% = 1. All you need to do is to find the probability for the other three players (since there are five players in the team). Choosing three players out of seven (excluding Mike and Ted) is 7C3 = 35.

:)
User avatar
demmy
User avatar
Joined: 24 Aug 2007
Last visit: 19 Sep 2007
Posts: 9
Posts: 9
Kudos: 0
Mike and Ted are among the nine players a basketball coach 13 Sep 2007, 14:08
Kudos
Add Kudos
Bookmarks
Bookmark this Post
KillerSquirrel
demmy
Just how you get the 7C3. 9C5 I understand. Many thanks.

You need to choose five players out of nine. But two of those players are already know to be Mike and Ted, so the probability of choosing Mike and Ted is 100% = 1. All you need to do is to find the probability for the other three players (since there are five players in the team). Choosing three players out of seven (excluding Mike and Ted) is 7C3 = 35.

:)
Show more


Much Appreciated..Thanks man



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!