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tinman1412
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Whatever
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tinman1412
Sorry for the confusion.

Katie leaves the house, and 30 minutes later, Scott goes after her. He is moving along the same path. At their rates, how long has Katie traveled before he catches her?


How can you determine this unless you know the speed of Scott ??
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Whatever
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I got:

1,5 km Katia will travel it 30 min.
1.5 + 3*x = 5*x
x = 0.75
5*x = 3.75

Is the answer 3.75 km?
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Amit05
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Whatever
I got:

1,5 km Katia will travel it 30 min.
1.5 + 3*x = 5*x
x = 0.75
5*x = 3.75

Is the answer 3.75 km?


OOhhhh I missed that 5 miles in the 1st post..
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tinman1412
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Yes, the answer is 3.75
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GMATBLACKBELT
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tinman1412
Scott and Katie leave Scott's house at 2:00 p.m. She walks toward the park at a rate of 3 miles per hour. 30 minutes later, Scott realizes she has forgotten something and runs after her at a rate of 5 miles per hour. How far has katie traveled before Scott catches up to her?

Please provide answer and explanation



Think Ive seen this one before. So I assume that they both don't leave the house at the same time.

Use d=rt

Scott: d=5t
Katie: d=3(t+1/2) 30min=1/2hr

make equations equal to each other.

5t=3t+3/2--> 2t=3/2--> t=3/4

Plug in for Katie

d=3(3/4+1/2) --> 15/4mi aprox 4mi (just know it is less than 4mi).

if u wanna calculate it all the way out 3.75mi
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GMATBLACKBELT
tinman1412
Scott and Katie leave Scott's house at 2:00 p.m. She walks toward the park at a rate of 3 miles per hour. 30 minutes later, Scott realizes she has forgotten something and runs after her at a rate of 5 miles per hour. How far has katie traveled before Scott catches up to her?

Please provide answer and explanation


Think Ive seen this one before. So I assume that they both don't leave the house at the same time.

Use d=rt

Scott: d=5t
Katie: d=3(t+1/2) 30min=1/2hr

make equations equal to each other.

5t=3t+3/2--> 2t=3/2--> t=3/4

Plug in for Katie

d=3(3/4+1/2) --> 15/4mi aprox 4mi (just know it is less than 4mi).

if u wanna calculate it all the way out 3.75mi


yep. 3.75 miles
this is a MGMAT question on page 30
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tinman1412
Scott and Katie leave Scott's house at 2:00 p.m. She walks toward the park at a rate of 3 miles per hour. 30 minutes later, Scott realizes she has forgotten something and runs after her at a rate of 5 miles per hour. How far has katie traveled before Scott catches up to her?

Please provide answer and explanation


3.75 km. ran Scott. poor :(

Sk=(t+1/2)*3
Ss=t*5
Ss=Sk

(t+1/2)*3=t*5

t=0.75 hours

Sk=3.75



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