MGMAT Problem 2.

Question

Can anyone solve this not picking #s, and by using logic?

What is the remainder when 25 is divided by positive integer j?

(1) j is even.

(2) j < 9

nevergiveup · Answer

Statement 1, if j is an even number and also happen to be a multiple of 5, the remiander will be different from if j is an even number and not a multiple of 5, so this is insufficient

Statement 2, j<9 contains no even number which also happen to be a multiple of 5, so the remainder will always be 1; therefore, sufficient

Answer B

bajaj · Answer

j can also be 1 and in that case the remainder will be 1... therefore C is correct

yezz · Answer

from 1

25/2 remainder is 1

25/4 remainder is 1

25/6 remainder is 1

25/10 remainder is 5.......multiple solutions ...insuff

from 2

25/8 remainder is 1

25/7 remainder is 4........insuff

combining

remiander of 25 when devided by (2,4,6,8) is 1 suff

my naswer is d

yezz · Answer

my bad , yes c. killer mistakes :lol:

devilmirror · Answer

Y = pX + q
Y = numerator
X = denominator
q = remainder

25 = p(X) + q

(1) j is even
25 = p(X) + q
25 / X = p + q / X

X = 2; 25 / 2 = 12 + 1/2; q = 1
X = 4; 25 / 4 = 6 + 1/4; q = 1
X = 6; 25 / 6 = 4 + 1/6; q = 1
X = 8; 25 / 8 = 3 + 1/8; q = 1
X = 10; 25 / 10 = 2 + 5/10; q = 5

There are two answers for the remainder. Insufficient.

(2) j < 9
X =1; 25 / 1 = 25 + 0; q = 0
X = 2; 25 /2 = 12 + 1/2; q = 1

There are two answers for the remainder. Insufficient.

(1) & (2)
All even integers that are less than 9 give the remainder = 1. Sufficient.

The answer is C.

pm4553 · Answer

Agree with C.

I worked with numbers though.

MGMAT Problem 2.

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