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pattydread
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a painter calculated the amount of paint needed to cover the 19 Aug 2008, 08:22
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a painter calculated the amount of paint needed to cover the four wall of a window less room, but mistakenly assumed that the walls were 9ft tall when they were in fact 10ft tall. his initial calcualtion indicated that he would need 18 cans of paint. If each can of paint can cover an area of 25 square feet, what is the actual number of cans needed to paint the room?

19

20

20 1/2

21

21 1/2



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a painter calculated the amount of paint needed to cover the 19 Aug 2008, 08:34
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pattydread
a painter calculated the amount of paint needed to cover the four wall of a window less room, but mistakenly assumed that the walls were 9ft tall when they were in fact 10ft tall. his initial calcualtion indicated that he would need 18 cans of paint. If each can of paint can cover an area of 25 square feet, what is the actual number of cans needed to paint the room?

19

20

20 1/2

21

21 1/2
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Initial calc = 25*18 = 450sq ft

Let x be width of one wall and y of other.

9x + 9y + 9x + 9y = 18 (x + y) = 450
x + y = 25

When height = 10

Area = 25*10*2 = 500

Therefore cans required = 20
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subarao
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a painter calculated the amount of paint needed to cover the 19 Aug 2008, 09:59
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let x is the width of wall.
So for the 9 ft tall wall, the area is 9x and he would need 18 cans of paint
If the actual length is 10 ft then for 10x he would need 18/9x*10= 20 can of paint




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a painter calculated the amount of paint needed to cover the four wall of a window less room, but mistakenly assumed that the walls were 9ft tall when they were in fact 10ft tall. his initial calcualtion indicated that he would need 18 cans of paint. If each can of paint can cover an area of 25 square feet, what is the actual number of cans needed to paint the room?
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judokan
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a painter calculated the amount of paint needed to cover the 19 Aug 2008, 10:47
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a painter calculated the amount of paint needed to cover the four wall of a window less room, but mistakenly assumed that the walls were 9ft tall when they were in fact 10ft tall. his initial calcualtion indicated that he would need 18 cans of paint. If each can of paint can cover an area of 25 square feet, what is the actual number of cans needed to paint the room?

Assme the perimeter of the room is x
y is the actual required no. of can

9x=18*25
x = 50 sq feet

actual total area = 50*10 = 500
y = 500/25 = 20



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!