Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2512:30 AM EDT
-01:30 AM EDT
At one point, she believed GMAT wasn’t for her. After scoring 595, self-doubt crept in and she questioned her potential. But instead of quitting, she made the right strategic changes. The result? A remarkable comeback to 695. Check out how Saakshi did it.
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
20 Jun 2019, 02:30
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
28% (03:18) correct
72%
(02:45)
wrong
based on 178
sessions
History
Date
Time
Result
Not Attempted Yet
In a survey on the popularity of magazines A,B and C among 100 pupils, 39 pupils like A, 36 like B, 45 like C, 14 like A and B only, 11 like B and C only, 5 like A and C only. Find the maximum number of pupils who do not like any of the magazines.
A) 10
B) 12
C) 20
D) 32
E) 48
A) 10
B) 12
C) 20
D) 32
E) 48
20 Jun 2019, 11:44
Kudos
Bookmarks
It's a very good problem.
Let 'x' pupil don't read any magazine and 'y' pupil read all 3 magazines
100-x= 39+36+45-14-11-5-2y
x=10+2y
We need to maximize the value of 'y' in order to maximize the value of x
y can be maximize when 11-y=0 or y=11
{If y were greater than 11, the pupil who read only magazine would be negative} You can clearly see that in the diagram below
The maximum number of pupils who do not like any of the magazines= 10+2*11=32
Let 'x' pupil don't read any magazine and 'y' pupil read all 3 magazines
100-x= 39+36+45-14-11-5-2y
x=10+2y
We need to maximize the value of 'y' in order to maximize the value of x
y can be maximize when 11-y=0 or y=11
{If y were greater than 11, the pupil who read only magazine would be negative} You can clearly see that in the diagram below
The maximum number of pupils who do not like any of the magazines= 10+2*11=32
Attachments
dgdg.png [ 11.42 KiB | Viewed 7438 times ]
General Discussion
20 Jun 2019, 05:47
Kudos
Bookmarks
Arvind42
\(None_{max} =\) 100 - (39+36+45-14-11-5-2*0(all three)) = 10
Answer: Option A
