The no. of residents in town T is 20,000. We, need to find the % of residents born in town T.
As 60% of them are female, the no. of female residents = 60% or (3/5) * 20,000 = 12,000;
So, the no. of male residents = 20,000 - 12,000 = 8,000;
We can assign the no. of Male and Female born in town T as MB and FB respecitively.
Similary, we can assign the no. of Male and Female not born in town T as MNB and FNB respectively.
Statement (1):
FB = 2 * MNB; Insufficient as we do not know the ratio of Born and Not Born.
Statement (2):
FNB = 2 * FB;
Since, we know the total no. of female residents in town T as 12,000, they can be classified as either Born or Not Born in town T.
Therefore, FB + FNB = 12,000;
FB + 2FB = 12,000;
3FB = 12,000;
FB = 4,000 and therefore FNB = 8,000;
Since we do not know the male strength born in town T, this statement is Insufficient too.
Combining, MNB = FB/2 = 4,000/2 = 2,000;
Therefore, MB = 8,000 - 2,000 = 6,000;
% of residents born in town T = (FB + MB)/Total = 4,000 + 6,000 = 10,000/20,000 = 50%;
Ans is (C).
Note: Most of the calculation done here is not required as it is a DS question. Press kudos if you think my explanation makes sense.