|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
04 Dec 2019, 02:33
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
67% (01:42) correct
33%
(01:38)
wrong
based on 183
sessions
History
Date
Time
Result
Not Attempted Yet
If \(x ≠ 0\), is \(\frac{x^2 + 1}{x} > y\)?
(1) \(x = y\)
(2) \(y > 0\)
Are You Up For the Challenge: 700 Level Questions
(1) \(x = y\)
(2) \(y > 0\)
Are You Up For the Challenge: 700 Level Questions
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
04 Dec 2019, 06:03
Kudos
Bookmarks
If \(x ≠ 0\), is \(\frac{x^2 + 1}{x} > y\)?
Or \(x+\frac{ 1}{x} > y\)
(1) \(x = y\)
Is \(x+\frac{ 1}{x} > y\)......\(x+\frac{ 1}{x} > x...........\frac{1}{x}>0\)?
If x>0, yes, but if x<0, no.
Insuff
(2) \(y > 0\)
Is \(x+\frac{ 1}{x} > y>0\)?
If x>0, yes, but if x<0, no.
Insuff
Combined
We know x=y>0, so answer is YES.
C
Or \(x+\frac{ 1}{x} > y\)
(1) \(x = y\)
Is \(x+\frac{ 1}{x} > y\)......\(x+\frac{ 1}{x} > x...........\frac{1}{x}>0\)?
If x>0, yes, but if x<0, no.
Insuff
(2) \(y > 0\)
Is \(x+\frac{ 1}{x} > y>0\)?
If x>0, yes, but if x<0, no.
Insuff
Combined
We know x=y>0, so answer is YES.
C
17 Jun 2025, 01:30
Kudos
Bookmarks
Automated notice from GMAT Club BumpBot:
A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
This post was generated automatically.
A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
This post was generated automatically.
