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30 Nov 2025, 23:06
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
74% (01:25) correct
26%
(01:30)
wrong
based on 122
sessions
History
Date
Time
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Not Attempted Yet
Were the total sales of company Y in 1992 greater than the total sales of company Y in 1987?
(1) In 1988, the total sales of company Y increased by 1.2% over the total sales in 1987.
(2) In each year from 1989 to 1992, the total sales of company Y decreased by 0.5% from the previous year.
(1) In 1988, the total sales of company Y increased by 1.2% over the total sales in 1987.
(2) In each year from 1989 to 1992, the total sales of company Y decreased by 0.5% from the previous year.
ankushsambare
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01 Dec 2025, 03:06
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Solution (simple, human-like, copy-paste friendly):
We want to know:
Were sales in 1992 > sales in 1987?
Let
S87 = sales in 1987
S88 = sales in 1988
S89, S90, S91, S92 follow.
### Statement (1)
S88 = S87 × 1.012
This only compares 1988 to 1987.
We know nothing about 1989–1992.
So we cannot compare 1992 to 1987.
Not sufficient.
### Statement (2)
From 1989 to 1992, sales drop 0.5% each year.
But we do NOT know sales in 1988 or 1987, or whether sales went up or down before 1989.
So we cannot compare 1992 to 1987.
Not sufficient.
### Combine (1) and (2)
Little calculation but if you think strcutrally you will understand that, S92 < S87 always.
We now know:
S88 = S87 × 1.012
Then each year 1989–1992 drops 0.5%.
So:
S89 = S88 × 0.995
S90 = S89 × 0.995
S91 = S90 × 0.995
S92 = S91 × 0.995
Compute overall factor from 1988 → 1992:
0.9954 ≈ 0.9801
So
S92 = S88 × 0.9801
S92 = (S87 × 1.012) × 0.9801
S92 ≈ S87 × (1.012 × 0.9801)
S92 ≈ S87 × 0.9917
0.9917 < 1
So S92 < S87 always.
We can answer the question: No, 1992 sales were NOT greater than 1987.
Together sufficient.
Answer: C
We want to know:
Were sales in 1992 > sales in 1987?
Let
S87 = sales in 1987
S88 = sales in 1988
S89, S90, S91, S92 follow.
### Statement (1)
S88 = S87 × 1.012
This only compares 1988 to 1987.
We know nothing about 1989–1992.
So we cannot compare 1992 to 1987.
Not sufficient.
### Statement (2)
From 1989 to 1992, sales drop 0.5% each year.
But we do NOT know sales in 1988 or 1987, or whether sales went up or down before 1989.
So we cannot compare 1992 to 1987.
Not sufficient.
### Combine (1) and (2)
Little calculation but if you think strcutrally you will understand that, S92 < S87 always.
We now know:
S88 = S87 × 1.012
Then each year 1989–1992 drops 0.5%.
So:
S89 = S88 × 0.995
S90 = S89 × 0.995
S91 = S90 × 0.995
S92 = S91 × 0.995
Compute overall factor from 1988 → 1992:
0.9954 ≈ 0.9801
So
S92 = S88 × 0.9801
S92 = (S87 × 1.012) × 0.9801
S92 ≈ S87 × (1.012 × 0.9801)
S92 ≈ S87 × 0.9917
0.9917 < 1
So S92 < S87 always.
We can answer the question: No, 1992 sales were NOT greater than 1987.
Together sufficient.
Answer: C
01 Dec 2025, 12:20
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clearly 1 and 2 are individually non sufficient to find out the relation between the values of 87 to 92.
however 1 and 2 together sufficient to sort out the relation between the values of 87 to 92, no need to do any type of calculation just need to find out the sufficiency.
hence C
however 1 and 2 together sufficient to sort out the relation between the values of 87 to 92, no need to do any type of calculation just need to find out the sufficiency.
hence C
