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03 Mar 2020, 03:54
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D
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Difficulty:
15%
(low)
Question Stats:
75% (00:47) correct
25%
(00:48)
wrong
based on 209
sessions
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What is the value of k^2 + k?
(1) The value of k + 1 is 1.
(2) The value of k^2 is 0.
(1) The value of k + 1 is 1.
(2) The value of k^2 is 0.
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
03 Mar 2020, 22:51
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Bunuel
\(k^2+k=k(k+1)\) so we are looking for product of two consecutive integers, k and k+1...
(1) The value of k + 1 is 1.
=> k+1=1...k=0, so k(k+1)=0
Suff
(2) The value of k^2 is 0
=> k^2=0...k=0, so k(k+1)=0
Suff
D
04 Mar 2020, 00:21
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This is an easy question on Algebraic expressions and equations. To find out the value of the given expression viz., \(k^2\) + k, we will need the value of k. Any such information that gives us a unique value of k will be sufficient information.
Let us break down the given expression as k(k+1) (which is essentially the product of two consecutive numbers).
From statement I alone, k+1 = 1. This means that k = 0. If k=0, k (k+1) = 0. Statement I alone is sufficient. Answer options B, C and E can be eliminated.
Possible answer options are A or D.
From statement II alone, \(k^2\) = 0. Note that \(k^2\) is a term with an even power, therefore, \(k^2\) will always be non-negative. The smallest value of \(k^2\) will be zero when k=0.
So, since we know that \(k^2\)=0, we can conclude that k=0. If k=0, k(k+1) = 0. Statement II alone is sufficient. Answer option A can be eliminated.
The correct answer option is D.
Hope that helps!
Let us break down the given expression as k(k+1) (which is essentially the product of two consecutive numbers).
From statement I alone, k+1 = 1. This means that k = 0. If k=0, k (k+1) = 0. Statement I alone is sufficient. Answer options B, C and E can be eliminated.
Possible answer options are A or D.
From statement II alone, \(k^2\) = 0. Note that \(k^2\) is a term with an even power, therefore, \(k^2\) will always be non-negative. The smallest value of \(k^2\) will be zero when k=0.
So, since we know that \(k^2\)=0, we can conclude that k=0. If k=0, k(k+1) = 0. Statement II alone is sufficient. Answer option A can be eliminated.
The correct answer option is D.
Hope that helps!
