Bunuel
Given: a, b, and c are consecutive integer, such that a < b < c Target question: Is a + b + c EVEN? Statement 1: abc = 0 This tells us that a = 0, b = 0 or c = 0
Here are two possible cases:
Case a: a = 0, b = 1 and c = 2. In this case, a + b + c = 0 + 1 + 2 = 3 (odd). So, the answer to the target question is
NO, a + b + c is NOT evenCase b: a = -1, b = 0 and c = 1. In this case, a + b + c = -1 + 0 +1 = 0 (even). So, the answer to the target question is
YES, a + b + c IS evenSince we cannot answer the
target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: a + c = 0We already know that a, b, and c are consecutive integers, AND a < b < c
So, if a + c = 0, we can be certain that a = -1, b = 0 and c = 1
In this case, a + b + c = -1 + 0 + 1 = 0 (even). So, the answer to the target question is
YES, a + b + c IS evenSince we can answer the
target question with certainty, statement 2 is SUFFICIENT
Answer: B
Cheers,
Brent