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If a, b, and c are consecutive integers, such that a < b < c, is their

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If a, b, and c are consecutive integers, such that a < b < c, is their  [#permalink]

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New post 06 Dec 2019, 06:12
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If a, b, and c are consecutive integers, such that a < b < c, is their  [#permalink]

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New post Updated on: 09 Dec 2019, 09:19
1
Top Contributor
Bunuel wrote:
If a, b, and c are consecutive integers, such that a < b < c, is their sum even?

(1) abc = 0
(2) a + c = 0

Are You Up For the Challenge: 700 Level Questions


Given: a, b, and c are consecutive integer, such that a < b < c

Target question: Is a + b + c EVEN?

Statement 1: abc = 0
This tells us that a = 0, b = 0 or c = 0
Here are two possible cases:
Case a: a = 0, b = 1 and c = 2. In this case, a + b + c = 0 + 1 + 2 = 3 (odd). So, the answer to the target question is NO, a + b + c is NOT even
Case b: a = -1, b = 0 and c = 1. In this case, a + b + c = -1 + 0 +1 = 0 (even). So, the answer to the target question is YES, a + b + c IS even
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: a + c = 0
We already know that a, b, and c are consecutive integers, AND a < b < c
So, if a + c = 0, we can be certain that a = -1, b = 0 and c = 1
In this case, a + b + c = -1 + 0 + 1 = 0 (even). So, the answer to the target question is YES, a + b + c IS even
Since we can answer the target question with certainty, statement 2 is SUFFICIENT

Answer: B

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Brent
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Originally posted by GMATPrepNow on 06 Dec 2019, 07:32.
Last edited by GMATPrepNow on 09 Dec 2019, 09:19, edited 1 time in total.
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Re: If a, b, and c are consecutive integers, such that a < b < c, is their  [#permalink]

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New post 08 Dec 2019, 23:59
2
GMATPrepNow wrote:
Bunuel wrote:
If a, b, and c are consecutive integers, such that a < b < c, is their sum even?

(1) abc = 0
(2) a + c = 0

Are You Up For the Challenge: 700 Level Questions


Given: a, b, and c are consecutive integer, such that a < b < c

Target question: Is a + b + c EVEN?

Statement 1: abc = 0
This tells us that a = 0, b = 0 or c = 0
Here are two possible cases:
Case a: a = 0, b = 1 and c = 2. In this case, a + b + c = 0 + 1 + 2 = 3 (odd). So, the answer to the target question is NO, a + b + c is NOT even
Case b: a = 1, b = 2 and c = 3. In this case, a + b + c = 1 + 2 +3 = 5 (even). So, the answer to the target question is YES, a + b + c IS even
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: a + c = 0
We already know that a, b, and c are consecutive integers, AND a < b < c
So, if a + c = 0, we can be certain that a = -1, b = 0 and c = 1
In this case, a + b + c = -1 + 0 + 1 = 0 (even). So, the answer to the target question is YES, a + b + c IS even
Since we can answer the target question with certainty, statement 2 is SUFFICIENT

Answer: B

Cheers,
Brent


Dear GMATPrepNow ,
In Statement 1, It is given : abc=0
In your case b, You have taken values,a = 1, b = 2 and c = 3 Which cannot be Zero, if we multiply them.
Hope you Got my point, Pls explain if i'm wrong.

Regards,
Rajat Chopra
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Re: If a, b, and c are consecutive integers, such that a < b < c, is their  [#permalink]

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New post 09 Dec 2019, 09:20
Top Contributor
rajatchopra1994 wrote:
Dear GMATPrepNow ,
In Statement 1, It is given : abc=0
In your case b, You have taken values,a = 1, b = 2 and c = 3 Which cannot be Zero, if we multiply them.
Hope you Got my point, Pls explain if i'm wrong.

Regards,
Rajat Chopra


Oops, the catch!
I've edited my response accordingly.
Kudos for you!!!!

Cheers,
Brent
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Re: If a, b, and c are consecutive integers, such that a < b < c, is their   [#permalink] 09 Dec 2019, 09:20
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