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03 May 2009, 21:06
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03 May 2009, 21:59
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B is correct.
Y >= 0 means y is not negative.
1. lx-3l >= y
In this case, x could have any (-ve, 0 or +ve) value. Its not sufficient.
2. lx-3l =< -y
In this case, lx-3l is always equal to 0 or +ve. Since y is >=0, y cannot be +ve to have statement 2 to be true.
So lx-3l must be 0 and hence x = 3. Its sufficient.
B.
Y >= 0 means y is not negative.
1. lx-3l >= y
In this case, x could have any (-ve, 0 or +ve) value. Its not sufficient.
2. lx-3l =< -y
In this case, lx-3l is always equal to 0 or +ve. Since y is >=0, y cannot be +ve to have statement 2 to be true.
So lx-3l must be 0 and hence x = 3. Its sufficient.
B.
04 May 2009, 04:53
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Yes, It is answer B.
(1) |x-3| ≥ y
This statement will hold true for several values of x and y.
for y = 0, x =
to 
for y = 1, x = ( to 2) and (4 to )
for y = 2, x = ( to 1) and (5 to )
...
and so on
(2) |x-3| ≤ -y
A mod can never be less than or equal to a negative value.
example,
for y = 1, |x-3| can never be less than -y=-1.
for y = 2, |x-3| can never be less than -y=-2.
-y ≠ +ve value, because of precondition that y ≥ 0
The only value of y, for which this statement is true is y = 0.
|x-3| ≤ -(0) → |x-3| ≤ 0 → x = 0, for no positive or negative value, this condition will hold true.
hope it helps.
(1) |x-3| ≥ y
This statement will hold true for several values of x and y.
for y = 0, x =
to for y = 1, x = (
to 2) and (4 to )for y = 2, x = (
to 1) and (5 to )...
and so on
(2) |x-3| ≤ -y
A mod can never be less than or equal to a negative value.
example,
for y = 1, |x-3| can never be less than -y=-1.
for y = 2, |x-3| can never be less than -y=-2.
-y ≠ +ve value, because of precondition that y ≥ 0
The only value of y, for which this statement is true is y = 0.|x-3| ≤ -(0) → |x-3| ≤ 0 → x = 0, for no positive or negative value, this condition will hold true.
hope it helps.
