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03 May 2009, 21:06
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Re: x and y.......... [#permalink]
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03 May 2009, 21:59
B is correct. Y >= 0 means y is not negative. 1. lx3l >= y In this case, x could have any (ve, 0 or +ve) value. Its not sufficient. 2. lx3l =< y In this case, lx3l is always equal to 0 or +ve. Since y is >=0, y cannot be +ve to have statement 2 to be true. So lx3l must be 0 and hence x = 3. Its sufficient. B.
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Re: x and y.......... [#permalink]
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04 May 2009, 04:53
Yes, It is answer B. (1) x3 ≥ y This statement will hold true for several values of x and y. for y = 0, x = to for y = 1, x = ( to 2) and (4 to ) for y = 2, x = ( to 1) and (5 to ) ... and so on (2) x3 ≤ y A mod can never be less than or equal to a negative value. example, for y = 1, x3 can never be less than y=1. for y = 2, x3 can never be less than y=2. y ≠ +ve value, because of precondition that y ≥ 0 The only value of y, for which this statement is true is y = 0. x3 ≤ (0) → x3 ≤ 0 → x = 0, for no positive or negative value, this condition will hold true. hope it helps.



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Re: x and y.......... [#permalink]
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04 May 2009, 08:13
Agree on B. x can only be 0



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Re: x and y.......... [#permalink]
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04 May 2009, 22:22
goldeneagle94 wrote: Yes, It is answer B. (1) x3 ≥ y This statement will hold true for several values of x and y. for y = 0, x = to for y = 1, x = ( to 2) and (4 to ) for y = 2, x = ( to 1) and (5 to ) ... and so on (2) x3 ≤ y A mod can never be less than or equal to a negative value. example, for y = 1, x3 can never be less than y=1. for y = 2, x3 can never be less than y=2. y ≠ +ve value, because of precondition that y ≥ 0 The only value of y, for which this statement is true is y = 0. x3 ≤ (0) → x3 ≤ 0 → x = 0, for no positive or negative value, this condition will hold true. hope it helps. Understood why B. Can you explain how to solve general equation type l something l > something else? please explain this for statement 1



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Re: x and y.......... [#permalink]
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05 May 2009, 03:41
bandit wrote: goldeneagle94 wrote: Yes, It is answer B. (1) x3 ≥ y This statement will hold true for several values of x and y. for y = 0, x = to for y = 1, x = ( to 2) and (4 to ) for y = 2, x = ( to 1) and (5 to ) ... and so on (2) x3 ≤ y A mod can never be less than or equal to a negative value. example, for y = 1, x3 can never be less than y=1. for y = 2, x3 can never be less than y=2. y ≠ +ve value, because of precondition that y ≥ 0 The only value of y, for which this statement is true is y = 0. x3 ≤ (0) → x3 ≤ 0 → x = 0, for no positive or negative value, this condition will hold true. hope it helps. Understood why B. Can you explain how to solve general equation type l something l > something else? please explain this for statement 1 Most of the time, values have to be substituted in the variable to determine its RANGE. Like in Statement 1, we found that the range is ANY value. for example, x+4 > 0, then range of x will be 4 < x < Try to figure out its RANGE.



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Re: x and y.......... [#permalink]
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05 May 2009, 18:25
Hi
Can you explain the below step alone.
x3 ≤ (0) → x3 ≤ 0 → x = 0, for no positive or negative value, this condition will hold true
Are we coming to tell x = 3 or x = 0.
i understood x3 ≤ 0 . A mod can never be less than or equal to a negative value. so  X3 =0 and x =3.
Please correct me if i am wrong.




Re: x and y..........
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05 May 2009, 18:25






