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The answer given was 1:3, I could not reckon how though !
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The answer given was 1:3, I could not reckon how though !

This answer doesn't make sense.

Using the givens, the triangle should look similar to the triangle in the attachment.

In order for BD/DC to be 1/3, BD = 1 and DC = 3.

But since triangle ADC has hypotenuse AD = 3. DC cannot equal 3.

In order for BD/DC to be 1/3, the original question should be rephrased so AC = 3 instead of AD = 3.

If AC = 3.

AB = 5 (b/c the triangle becomes 345 triangle).

and we are left with two equations and two unknowns where

AB + BD = AC + DC and BD + DC = 4.

which results in BD = 1 and DC = 3.
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I thought this problem was really hard, but actually it's really really simple.

We know that triangle ABC is a 3-4-5 triangle. simple from knowing AC = 3 and CB = 4

CB = 4 = CD + DB

Equation 1 : CD + DB = 4

We are told that P(ABD) = P(ADC)

3 + CD + AD = 5 + DB + AD

Equation 2 : CD - DB = 2

CD + DB = 4
CD - DB = 2
2CD = 6

CD = 3

Therefore DB = 1

And finally CD:DB > 3:1 or whatever direction the question asked.

Essentially you don't need to know AD.
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