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plug in nos.

Let x = 14, 23, 32
x/9
Reminder is 5

Let 3x = 3*14, 3*23, 3*32
3x/9
Reminder is 6
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Are we not supposed to reduce the fraction in such questions? I'm getting 2 as a remainder to this problem. I reduced 42/9 to 14/3 leaving 2 as the remainder. Please point out my error.

Thanks



yezz
alimad
When the positive integer x is divided by 9, the remainder is 5. What is the remainder when 3x is divided by 9?
0

1

3

4

6


x= 9k+5 ie: 3x = 27k+15, 27k+15 / 9 = a reminder of 15-9 = 6
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alimad
When the positive integer x is divided by 9, the remainder is 5. What is the remainder when 3x is divided by 9?

A. 0
B. 1
C. 3
D. 4
E. 6

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alimad
When the positive integer x is divided by 9, the remainder is 5. What is the remainder when 3x is divided by 9?

A. 0
B. 1
C. 3
D. 4
E. 6

*Test like approach:*
choose a number that satisfies the given constraint I'm. Remainder 5 when divided by 9.
Such number, x = 5, 14, 23 etc.

Choose smallest and find 3x
I.e. 3x= 15
Divide by 9 and check remainder = 6

*Point to learn*
A number when divided by 9 leaves remainder 5 will be of the form = 9a+5

I.e. x= 9a+5

Now 3x = 3(9a+5)= 27a+15

When 3x is divided by 9 then 27a is always divisible hence remainder will be obtained by getting the remainder when 15 is divided by 9

Answer : Remainder =6

Answer option E
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alimad
When the positive integer x is divided by 9, the remainder is 5. What is the remainder when 3x is divided by 9?

A. 0
B. 1
C. 3
D. 4
E. 6


We can let x = 14 since the remainder when 14 is divided by 9 is 5. So 3x = 42 and 42/9 = 4 R 6. Therefore, the remainder is 6.

Alternate Solution:

Since the remainder from the division of x by 9 is 5, we can write x = 9s + 5 for some positive integer s.

Multiplying by 3, we get 3x = 27s + 15 = 27s + 9 + 6 = 9(3s + 1) + 6. Thus, the quotient is 3s + 1 and the remainder is 6.

Answer: E
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Let the number x be in the form 9q + 5

3x is 27q + 15 and this on dividing by 9 will give us a remainder same as the remainder when 15 is divided by 9 which is 6.

(option e)

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When the positive integer x is divided by 9, the remainder is 5. What is the remainder when 3x is divided by 9?

Lets solve the problem using two methods

Method 1: Substitution

When the positive integer x is divided by 9, the remainder is 5
Let x = 9 + 5 = 14
=> 3x = 14*3 = 42

3x divided by 9 = 42 divided by 9, will give 6 remainder (36 + 9)

Method 2: Algebra

When the positive integer x is divided by 9, the remainder is 5.

Dividend = Divisor * Quotient + Remainder

=> x = 9*a + 5 (where a is the quotient)
=> x = 9a + 5 ...(1)

What is the remainder when 3x is divided by 9?

=> 3x = 3*(9a + 5) = 27a + 15

Remainder of 3x by 9 = Remainder of 27a + 15 by 9 = Remainder of 27a by 9 + Remainder of 15 by 9 = 0 + 6 = 6

So, Answer will be E
Hope it helps!

Watch the following video to MASTER Remainders

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Given: When the positive integer x is divided by 9, the remainder is 5.

Hence, x = 9k+5

Thus, 3x = 27k+15

Dividing 3x by 9:

Remainder when 27k is divided by 9 = 0, and remainder when 15 is divided by 9 is 6. Hence, the overall remainder is 6 (Option E)
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