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Shameek Can u please elaborate

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suchita2409
Shameek Can u please elaborate

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suchita2409
Consider comparing \(\frac{x}{y}\) to \(\frac{(x+1)}{(y+1)}\) What do we do - we cross multiply and compare. For eg. \(\frac{10}{11}\) compared to \(\frac{11}{12}\) -> 120 compared to 121 implies \(\frac{10}{11} < \frac{11}{12}\)

Therefore \(\frac{x}{y}\) compared to \(\frac{(x+1)}{(y+1)}\) (Or any positive number added to numerator and denominator)
x(y+1) compared to y(x+1) which is nothing but x compared to y

Thus if x < y then \(\frac{(x+1)}{(y+1)} > \frac{x}{y}\)
If x > y then \(\frac{(x+1)}{(y+1)} < \frac{x}{y} \)

Note x and y are nothing but Numerator and Denominators. You can check using values for x = 10 y=11 i.e. x<y and then x=11 y=10 x>y

Hope this makes better sense :)
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Thank u so much.
This problem chewed out my brain.

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i just listed out the relavent digits and compared:

a) 9752 9755
b) 9866 9869
c) 9887 9890
d) 9856 9859
e) 9865 9868

Left divided by right should be the largest, which is C.
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