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souvonik2k
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I have a easy method, you may consider...
let, x do the work in x days
y do the work in 3x days
z do the work in 6x days
So,
X's 1 day's work is 1/x part
Y's 1 day's work is 1/3x part
Z's 1 day's work's is 1/6x part
So, (X+ Y + Z)'s 1 day's work = 1/x + 1/3x + 1/6x
Again,
(X+ Y + Z) do the work in 10 days
so, their 1 day's work is 1/10
According to the question,
1/x + 1/3x + 1/6x =1/10
Solving this we can get x=15

So, the number of day by z to do the work is = 6x
--------------------------------------------------- = 6 * 15
--------------------------------------------------- = 90 days.
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souvonik2k
X, Y and Z together can complete a job in 10 days. The rate of work of X is three times that of Y, which, in turn is twice that of Z. What is the time taken by Z alone to complete the job?
A) 60 days
B) 80 days
C) 90 days
D) 120 days
E) 150 days


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