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div10
If r is an integer and 9q = 243^r, which of the following expresses q in terms of r?

A. q=27^r
B. q=81^(r−9)
C. q=3^(r−3)
D. q=3^(5(r−2))
E. q=3^(5r−2)


hi..

\(9q = 243^r.... 3^2*q=(3^5)^r...........q=\frac{3^{5r}}{3^2}=3^{5r-2}\)
E
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div10
If r is an integer and 9q = 243^r, which of the following expresses q in terms of r?

A. q=27^r
B. q=81^(r−9)
C. q=3^(r−3)
D. q=3^(5(r−2))
E. q=3^(5r−2)
9q = 243^r

Or, \(3^2q = 3^{5r}\)

So, \(q = 3^{5r-2}\)

Thus, answer will be (E) \(q=3^(5r−2)\)
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\(9q=243^r\)
\(3^2q\)=\(3^{5r}\)
\(q=\frac{3^{5r}}{3^2}\)
\(q=3^{5r-2}\)
Answer E.
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9q = 243^r
=> q = 243^r/9 = 3^5r/3^2 = 3^(5r-2)

Ans: E.
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gracie90
I say E as well. I plugged in numbers (q=27, r=1) and then looked at which answer choice yields q.

(E) q=3^(5r−2)

27=3^3


I went with this first. But picking those numbers also allows for A to be correct which it is in fact not.

If testing numbers, be careful to test all the choices guys! If you get a duplicate, switch the numbers up.
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9q= 243^r can be simplified as q= (3^5r)/3^2
q=3^(5r-2)
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