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D
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Difficulty:
55%
(hard)
Question Stats:
63% (00:57) correct
38%
(00:48)
wrong
based on 8
sessions
History
Date
Time
Result
Not Attempted Yet
The combined cost of Car X and Car Y is 7250$. Had the Car X been 25% cheaper, and the Car Y been 20% costlier, Combined cost would have been 6,450$. How much Car X is costlier than Car Y?
A : 500
B : 800
C : 1000
D : 2750
E : 2250
A : 500
B : 800
C : 1000
D : 2750
E : 2250
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10 Mar 2018, 04:55
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Let say Car X is 4C1 as 25% = ¼ , Car Y is 5C2 as 20% = 1/5
Car X price decreased to 25% New price will become 3C1
Car Y price increased to 20% New price will become 6C2
Now we have 4C1 + 5C2 = 7250 & 3C1 + 6C2 = 6450 --- C1 – C2 = 800
Option D.
Car X price decreased to 25% New price will become 3C1
Car Y price increased to 20% New price will become 6C2
Now we have 4C1 + 5C2 = 7250 & 3C1 + 6C2 = 6450 --- C1 – C2 = 800
Option D.
10 Mar 2018, 09:21
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prady2231
I am getting $2750 as answer.
if car X is 25% cheaper - it's price doesn't become 1/4th -- but rather 3/4th of original price.
first equation : \(X+Y = 7250\)
second equation : \(0.75X + 1.20 Y = 6450\).
Solving both for X, Y we have : Y = 6750/3
using first equation and solution of Y to find X - Y ( ANswe r to prompt question of " how much is X costlier than Y)
We get \(X - Y = 2750\)
Please let me know what you guy's think.
Hope this helped....
