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Origin, O - (2,3)
A (-1,7) - Does not lie outside the circle, implies it is either on the circle or inside the circle.

Distance between (2,3) and (-1,7) = 5
So, radius of the circle <= 5

Q) Must lie inside the circle, implies NEITHER outside the circle NOR on the circle.

D < 5 ===> D!>=5

Point 1 - Distance between (2,3) and (0,7) ===> Less than 5
Point 2 - Distance between (2,3) and (5,-1) ===> Equals to 5
Point 3 - Distance between (2,3) and (-2,7) ===> More than 5

Answer is Only I.

Option A.

saswata4s
In the coordinate system, the center of a circle lies at (2, 3). If point A with coordinates (-1, 7) does not lie outside the circle, which of the following points must lie inside the circle?

I. (0, 7)
II. (5, -1)
III. (-2, 7)

A) I only
B) II only
C) III only
D) I and II only
E) None of the above
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Solution



If the point \(A (-1,7\)) does not lie outside the circle, then it can lie either on the circle or inside the circle as shown in the diagram.




Let us denote the distance between the point \(A (-1,7)\) and centre of the circle \((2,3)\) by \(D\).
    D= \(\sqrt{(2-(-1))^2+(3-7)^2}\)
    D= 5

Now, when the distance of point A is 5, then we are uncertain whether it lies on the circle or inside the circle.

However, if the distance of any point from centre is less than 5 then we can infer, that the point is certainly inside the circle.

Let us find the distance of all the points given in options.

1- (0,7)

Distance= \(\sqrt{(2-0)^2+(3-7)^2}\)
Distance= \(\sqrt{20}\), which is less than \(5\).

Hence (0,7) lies inside the circle.

2- (5, -1)

Distance= \(\sqrt{(2-5)^2+(3-(-1))^2}\)
Distance= \(5\)

3- (-2, 7)

Distance= \(\sqrt{(2-(-2))^2+(3-7)^2}\)
Distance= \(\sqrt{32}\), which is greater than \(5\).

Answer: A

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