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Originally posted by LMP on 08 Aug 2018, 07:08.
Last edited by generis on 08 Aug 2018, 07:49, edited 1 time in total.
Edited the question, renamed topic
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A school period is a block of time allocated for lessons, classes in schools. There are 6 periods in each working day of school. In how many ways can one organize 5 subjects such that each subject is allowed at least one period ?
A) 3600 B) 1800 C) 1400 D) 4000 E) 2000
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A school period is a block of time allocated for lessons, classes in schools. There are 6 periods in each working day of School . In how many ways can one organize 5 subjects such that each subject is allowed at least one period ?
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+1 for B.
5 subjects in 6 periods = 6P5 Remaining 1 period = 5P1
Since one subject is repeated twice, we need to divide the final arrangement by 2!
Total number of arrangement = ( 6P5 * 5P1 ) / 2! = 1800
A school period is a block of time allocated for lessons, classes in schools. There are 6 periods in each working day of school. In how many ways can one organize 5 subjects such that each subject is allowed at least one period ?
A) 3600 B) 1800 C) 1400 D) 4000 E) 2000
Show more
OA:B
Time slot................X X X X X X Subject choice.........5 4 3 2 1 -
Empty slot can be arranged in 6 position :X X X X X X;X X X X X X;X X X X X X;X X X X X X;X X X X X X; X X X X X X Empty Slot can be filled any of 5 subject,this will lead to 2 slots having same subjects
Total number of schedule of subject possible: \(\frac{5*4*3*2*1*(6*5)}{2!}=\frac{3600}{2}=1800\)
I have different way to solve the problem: Number of period = 6 Number of subject = 5 So let's say 5 subject are A,B,C,D,E. We know atleast 1 subject has to be repeated. If subject A is repeated. The AABCDE. by anagraming 6!÷2!. No. Of ways = same can be true for all 5 subjects. 5×6!÷2!= 1800
A school period is a block of time allocated for lessons, classes in schools. There are 6 periods in each working day of school. In how many ways can one organize 5 subjects such that each subject is allowed at least one period ?
A) 3600 B) 1800 C) 1400 D) 4000 E) 2000
Show more
Let the subjects be A, B, C, D, E & we have 6 periods to fill in. Hence one empty slot of period that can be filled by each of the 5 different periods.
Hence the arrangements will be of the form A B C D E _ , the empty slot "_", to be filled in by each subject as ( A B C D E A, A B C D E B, etc.)
Each of the arrangement can be re arranged within itself in 6!/2! ways
We get # of ways of organizing the periods as = (6!/2!) * 5 = 1800
Thanks, GyM
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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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